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3 years ago

Help !! No work is needed to be shown

Mathematics

1 answer:

o-na [289]3 years ago

5 0

Step-by-step explanation:

By Law of Indices, a^m / a^n = a^(m-n).

Therefore a² / a⁸ = a^(-6).

x = -6.

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The number of species of coastal dune plants in australia decreases as the latitude, in °s, increases. There are 34 species at 1

Bas_tet [7]

We have been given that the number of species of coastal dune plants in Australia decreases as the latitude, in °s, increases.

Further we know that there are 34 species at 11°s and 26 species at 44°s.

We can express the given information at two ordered pairs as shown below:

$(n,l)=(11,34)\text{ and }(n,l)=(44,26)$

Let us find slope of the line through these points:

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}=\frac{26-34}{44-11}=\frac{-8}{33}=-0.2424$

Therefore, we can write the equation of line in slope intercept form as:

$n=-0.2424l+b$

Where b is the y intercept, and we can find its value using one of the two points.

$34=-0.2424(11)+b\\34=-2.67+b\\b=34+2.67=36.67$

Therefore, the required equation of the linear function is:

$n=-0.2424l+36.67$

4 0

3 years ago

35 = 1/2(x-5)(x-14) what does x equal?

Yanka [14]

The answer is x=19.
Hope it helps! (:

3 0

3 years ago

Help me solve the binary operations please

son4ous [18]

Answer:

3*2= $\sf{\pink{\dfrac{4}{5}}}$

Step-by-step explanation:

Given that,

x*y= $\dfrac{(2x-y)}{(x+y}$

3*2=

$\dfrac{2(3)-2}{3+2}\\\\\dfrac{6-2}{5}\\\\\dfrac{4}{5}$

Therefore:-

$\therefore {3*2}=\dfrac{4}{5}$

6 0

2 years ago

Use linear approximation to approximate √25.3 as follows.

Sophie [7]

The idea is to use the tangent line to $f(x)=\sqrt x$ at $x=25$ in order to approximate $f(25.3)=\sqrt{25.3}$ .

We have

$f(x)=\sqrt x\implies f(25)=\sqrt{25}=5$

$f'(x)=\dfrac1{2\sqrt x}\implies f'(25)=\dfrac1{10}$

so the linear approximation to $f(x)$ is

$L(x)=f(5)+f'(5)(x-5)=5+\dfrac{x-5}{10}=\dfrac x{10}+\dfrac92$

Hence $m=\frac1{10}$ and $b=\frac92$ .

Then

$f(25.3)\approx L(25.3)=\dfrac{25.3}{10}+\dfrac92=\boxed{7.03}$

4 0

3 years ago

For what values do maximum r-values occur on the graph the polar equation

blagie [28]

Answer:

We have the function:

r = -3 + 4*cos(θ)

And we want to find the value of θ where we have the maximum value of r.

For this, we can see that the cosine function has a positive coeficient, so when the cosine function has a maximum, also does the value of r.

We know that the meaximum value of the cosine is 1, and it happens when:

θ = 2n*pi, for any integer value of n.

Then the answer is θ = 2n*pi, in this point we have:

r = -3 + 4*cos (2n*pi) = -3 + 4 = 1

The maximum value of r is 7

(while you may have a biger, in magnitude, value for r if you select the negative solutions for the cosine, you need to remember that the radius must be always a positive number)

5 0

3 years ago

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