Y=3 because it is horizantal line that is between 0 and 6
H=2f/m+1
subtract one from both sides
h-1=2f/m
multiply m to both sides
m*h-1=2f
divide 2 both sides
mh-1/2=F
(the whole left side of the equation is divided by 2 i just cant do it on the computer)
I one is 8x<24 and -8≤2x-4
Hence x <24/8 =3 and -4≤2x: divide by positive 2 to get -2≤x
Hence solution is -2≤x<3
Therefore c is the correct matching for 1.
2) 5x-2>13 or -4x≥8
i.e. 5x>15 or x≤8/(-4) = -2 (since dividing by negative inequality reverses)
Or x>3 or x ≤-2
Hence solution is two regions to the right of 3 excluding 3 and left of -2 including -2.
Graph b is the correct match.
3) -25≤9x+2<20
Subtract 2
-27≤9x<18: Now divide by positive 9
-3≤x<2
Hence graph is the region between -3 and 2 including only -3.
Graph a is correct matching for question 3.
Answer:
See below
Step-by-step explanation:
I think we had a question similar to this before. Again, let's figure out the vertical and horizontal distances figured out. The distance from C at x=8 to D at x=-5 is 13 units while the distance from C at y=-2 to D at y=9 is 11 units. (8+5=13 and 2+9=11, even though some numbers are negative, we're looking at their value in those calculations)
Next, we have to divide each distance by 4 so we can apply it to the ratio. 13/4=
and 11/4=
. Next, we need to read the question carefully. It's asking us to place the point in the ratio <em>3</em> to <em>1</em> from <em>C</em> to <em>D</em>. The point has to be closer to endpoint D because of this. Let's take each of our fractions, multiply them by 3, then add them towards the direction of endpoint D to get our answer (sorry if that sounds confusing):

Therefore, our point that partitions CD into a 3:1 ratio is (
).
I'm not sure if there was more to #5 judging by how part B was cut off. From what I can understand of part B, however, I believe that Beatriz started from endpoint D and moved towards C, the wrong direction. She found the coordinates for a 1:3 ratio point.
Also, for #6, since a square is a 2-dimensional object, the answer needs to be written showing that. The answer for #6 is 9 units^2.
Answer:
domain: x>3/5
Step-by-step explanation:
First we need to derive our function g(x) to get a new function g'(x)
To do this we will have to apply chain rule because we have an inner and outer functions.
Our G(x) = square root(3-5x)
Chain rule formula states that: d/dx(g(f(x)) = g'(f(x))f'(x)
where d/dx(g(f(x)) = g'(x)
g(x) is the outer function which is x^1/2
f(x) is our inner function which is 3-5x
therefore f'(x)= 1/2x^(-1/2) and f'(x) = -5
g'(f(x)) = -1/2(3-5x)^(-1/2)
Applying chain rule then g'(x) = 1/2 (3-5x)^(-/1/2)*(-5)
But the domain is the values of x where the function g'(x) is not defined
In this case it will be 3-5x > 0, because 3-5x is a denominator and anything divide by zero is infinity/undefined
which gives us x >3/5