Answer:
40 individuals
Explanation:
The homozygous recessive percentage is equal to q2.
Recessive genotype frequency, q 2 is 1/1000000 = 0.000001
therefore, q = 
= 
= 0.001 = allele "a" frequency
and p + q = 1, thus, p = 1 – q = 1 – 0.001 = 0.999
thus, the frequency of allele a = q = 0.001 and the frequency of allele A = p = 0.999
Carriers are heterozygous and are equal to 2pq.
So, 2pq = 2 x 0.999 x 0.001 x 20,000 = 39.96 (round of to 40)
Hence, 40 individuals will be expected to carry the recessive allele.
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