At a certain fast-food restaurant, 56% of customers order a chicken sandwich, 43% of customers order french fries, and 30% of cu

Question

2 years ago

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At a certain fast-food restaurant, 56% of customers order a chicken sandwich, 43% of customers order french fries, and 30% of cu

stomers order both a chicken sandwich and french fries. What is the probability that a randomly selected customer will order a chicken sandwich or french fries (or both items)?

Mathematics

1 answer:

Setler [38] · Answer 1 · 2023-07-19T06:21:23+03:00

The probability that a randomly selected customer will order a chicken sandwich or french fries is 36%

<h3>How to determine the probability?</h3>

The given parameters are:

P(Chicken) = 56%

P(Sandwich) = 43%

P(Both) = 30%

The required probability is:

P = P(Chicken) + P(Sandwich) - P(Both)

This gives

P = 56% + 43% - 30%

Evaluate

P = 36%

Hence, the probability that a randomly selected customer will order a chicken sandwich or french fries is 36%