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anzhelika [568]
2 years ago
15

X+y=5 x×y=6 Solve simultaneously with steps

Mathematics
1 answer:
igor_vitrenko [27]2 years ago
7 0

Answer:

(3, 2), (2, 3)

Step-by-step explanation:

x + y = 5

xy = 6

Solve the first equation for x.

x = 5 - y

Substitute 5 - y for x in the second equation.

xy = 6

(5 - y)y = 6

5y - y² = 6

y² - 5y + 6 = 0

Factor.

(y - 2)(y - 3) = 0

y - 2 = 0  or y - 3 = 0

y = 2  or y = 3

Now substitute 2 for y in the first equation and solve for x.

x + y = 5

x + 2 = 5

x = 3

One solution is x = 3; y = 2, or (3, 2).

Now substitute 3 for y in the first equation and solve for x.

x + y = 5

x + 3 = 5

x = 2

Another solution is x = 2; y = 3, or (3, 2).

Answer: (3, 2), (2, 3)

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Solve the equation for all real solutions in simplest form.<br> z^2 - 12z +9= -3
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Answer:

Solving the equation for all real solutions in simplest form.

z^2 - 12z +9= -3 we get \mathbf{z=10.9\: or\: z=1.1}

Step-by-step explanation:

We need to solve the equation for all real solutions in simplest form.

z^2 - 12z +9= -3

First simplifying the equation:

z^2 - 12z +9+3= -3+3\\z^2 - 12z +12= 0

Now, we can solve the equation using quadratic formula:

z=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

we have a = 1, b=-12 and c=12

Putting values in formula and finding values of x

z=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\z=\frac{-(-12)\pm\sqrt{(-12)^2-4(1)(12)}}{2(1)}\\z=\frac{12\pm\sqrt{144-48}}{2}\\z=\frac{12\pm\sqrt{96}}{2}\\z=\frac{12\pm9.8}{2}\\z=\frac{12+9.8}{2}\:or\:z=\frac{12-9.8}{2}\\z=10.9\:or\:z=1.1

So, we get value of z: z=10.9 or z=1.1

Solving the equation for all real solutions in simplest form.

z^2 - 12z +9= -3 we get \mathbf{z=10.9\: or\: z=1.1}

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3 years ago
Is this the right answer?
pychu [463]
Looks correct to me but i'm not 100% sure

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