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BartSMP [9]
2 years ago
11

Why might the t-test be more useful in actual practice when you are running statistics rather than a z-test? give an example of

a situation where you might use each of these and label their pros and cons.
Mathematics
1 answer:
KatRina [158]2 years ago
3 0

The t-test might be more useful in actual practice when standard deviation or variance is unknown.

<h3>What is a t-test?</h3>

The t-test is used to determine how the averages of various data sets differ from one another.

When variance is not provided, the T-test, a particular kind of parametric test, is used to determine how the means of two sets of data differ from one another. When variance is provided, the Z-test indicates a hypothesis test that determines whether the means of two datasets differ from one another.

Example of t-test: If you flip a coin 1,000 times, for instance, you can discover that the outcome is distributed normally over all trials.

Example of z-test: We are conducting research using information gathered from cohorts of students who have taken Elementary Statistics in the past.

T-tests are typically more suitable when addressing issues with small sample sizes, whereas z-tests are suitable for large sample sizes.

Using the t-test for an ordinal variable, their frequency is not even close to a normal distribution, and the arithmetic mean offers an unsuitable measure of location.

Because we frequently don't know the population standard deviation, Z-Tests have this drawback.

Learn more about t-tests here:

brainly.com/question/6589776

#SPJ4

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Graph the function y = 4x4 – 8x2 + 4. Which lists all of the turning points of the graph?
Serhud [2]

Answer:

4(x + 1)^{2}(x - 1)^{2}

Step-by-step explanation:

STEP 1:

The equation at the end of step 1

((4 (x^4)) -  2^3x^2) +  4

STEP 2:

The equation at the end of step 2:

(2^2x^4 -  2^3x^2) +  4

STEP 3:

STEP 4: Pulling out like terms

<u>4.1</u> Pull out like factors:

4x^4 - 8x^2 + 4  =   4(x^4 - 2x^2 + 1)

Trying to factor by splitting the middle term

<u>4.2</u> Factoring x^4 - 2x^2 + 1

The first term is, x^4 its coefficient is 1.

The middle term is,  -2x^2  its coefficient is -2.

The last term, "the constant", is +1.

Step-1: Multiply the coefficient of the first term by the constant   1 • 1 = 1

Step-2: Find two factors of  1  whose sum equals the coefficient of the middle term, which is -2.

-1 + -1 = -2 That's it

Step-3: Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -1  and  -1

                    x4 - 1x2 - 1x2 - 1

Step-4 : Add up the first 2 terms, pulling out like factors :

                   x2 • (x2-1)

             Add up the last 2 terms, pulling out common factors :

                    1 • (x2-1)

Step-5 : Add up the four terms of step 4 :

                   (x2-1)  •  (x2-1)

            Which is the desired factorization

Trying to factor as a Difference of Squares:

4.3      Factoring:  x2-1

Theory : A difference of two perfect squares,  A2 - B2  can be factored into  (A+B) • (A-B)

Proof :  (A+B) • (A-B) =

        A2 - AB + BA - B2 =

        A2 - AB + AB - B2 =

        A2 - B2

Note :  AB = BA is the commutative property of multiplication.

Note :  - AB + AB equals zero and is therefore eliminated from the expression.

Check : 1 is the square of 1

Check :  x2  is the square of  x1

Factorization is :       (x + 1)  •  (x - 1)

Trying to factor as a Difference of Squares:

4.4      Factoring:  x2 - 1

Check : 1 is the square of 1

Check :  x2  is the square of  x1

Factorization is :       (x + 1)  •  (x - 1)

Multiplying Exponential Expressions:

4.5    Multiply  (x + 1)  by  (x + 1)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is  (x+1)  and the exponents are :

         1 , as  (x+1)  is the same number as  (x+1)1

and   1 , as  (x+1)  is the same number as  (x+1)1

The product is therefore,  (x+1)(1+1) = (x+1)2

Multiplying Exponential Expressions:

4.6    Multiply  (x-1)  by  (x-1)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is  (x-1)  and the exponents are :

         1 , as  (x-1)  is the same number as  (x-1)1

and   1 , as  (x-1)  is the same number as  (x-1)1

The product is therefore,  (x-1)(1+1) = (x-1)2

Final result :

 4 • (x + 1)2 • (x - 1)2

4 0
3 years ago
Read 2 more answers
3 (14-7)-16 evaluate the expression?
storchak [24]
PEMDAS
14-7=7
3(7)-16
27-16=11
5 0
3 years ago
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Work the following pricing problems for services rendered. (Round to hundredths.) Hourly rate, worker A = $15.00 Hourly rate, wo
svlad2 [7]
Hello there :-)

Total cost of job=retail price of goods+labor cost+overhead

Labor cost
15×2.5+8×1+5.25×(3÷4)
=49.44 this is labor cost

Overhead= labor cost×overhead rate
Overhead=49.44×0.75=37.08

Now find total cost of job
Total cost of job=125.50+49.44+37.08
=212.02....answer

Hope it helps
7 0
3 years ago
35,710 written in scientific notation
Dmitrij [34]
The answer is 3571x10
4 0
3 years ago
Solve by the method of elimination by using multiplication. x-y=15 4x+2y=30
Studentka2010 [4]
The solution is y= -5 and x=10

7 0
4 years ago
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