Question

SOMEONE HELP

Answer 1

Answer:

D

Step-by-step explanation:

Given y varies directly as x and z then the equation relating them is

y = kxz ← k is the constant of variation

To find k use the condition y = $\frac{8}{3}$ when x = 1 and z = 4 , then

$\frac{8}{3}$ = k × 1 × 4 = 4k ( divide both sides by 4 )

$\frac{2}{3}$ = k

y = $\frac{2}{3}$ xz ← equation of variation

When x = 6 and z = 3 , then

y = $\frac{2}{3}$ × 6 × 3 = $\frac{2}{3}$ × 18 = 2 × 6 = 12

Answer 2

Answer:

the answer to this question is

d.)y=⅔xz;y(6,3)=12