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vivado [14]
2 years ago
11

The equation is 6a³+3b² when a=4 and b=1

Mathematics
2 answers:
zysi [14]2 years ago
7 0
Answer: 387

Step-by-Step Solution:

=> 6a^3 + 3b^2 ; when a = 4 and b = 1

Plug in the Values :-

= 6a^3 + 3b^2
= 6(4^3) + 3(1^2)
= 6(64) + 3(1)
= 384 + 3
=> 387
IRISSAK [1]2 years ago
3 0

Answer:

387

Step-by-step explanation:

6(4)³ + 3(1)²

6(64) + 3(1)

384 + 3

= 387

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In the given question, we can see a difference of squares

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Please help, thanks.​
Liula [17]

Answer:

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\frac{15}{4}   \div  \frac{3}{8}  =  \frac{15}{4}  \times  \frac{8}{3}  =  10

10 \times  \frac{25}{54}  =  \frac{250}{54}  = 4 \times \frac{17}{27}

b )

4 \times \frac{17}{27}  =  \frac{125}{27}  =

cube root =

\frac{5}{3}

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\frac{125}{27}  =  \frac{ \sqrt{25 \times 5} }{ \sqrt{3 \times 9} }  =  \frac{5 \sqrt{5} }{3 \sqrt{3} }

3 0
3 years ago
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