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3 years ago

Write an algebraic expression to represent each scenario. Part A: “the sum of 6 and y”

Mathematics

1 answer:

Nostrana [21]3 years ago

3 0

Answer:

6 + y

Step-by-step explanation:

Here, we want to write an algebraic expression to represent the situation

Mathematically, we want to add 6 and y

The algebraic expression will be;

6 + y

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Does anyone know how to do this please?

Lostsunrise [7]

Answer:

Step-by-step explanation:

3 0

3 years ago

What are the roots of this equation 2x^2+7x-3=0

Ludmilka [50]

Step-by-step explanation:

2x^2+7x-3=0

by doing splitting the middle term we get/ <u>using quadratic eq we get-</u>

Let's solve your equation step-by-step.

2x2+7x−3=0

For this equation: a=2, b=7, c=-3

2x2+7x+−3=0

Step 1: Use quadratic formula with a=2, b=7, c=-3.

−b±√b2−4ac

−(7)±√(7)2−4(2)(−3)

2(2)

x= −7±√73 /4

x= −7 4 + 1 4 √73 or x= −7 4 + −1 4 √73

Answer:

x= −7 4 + 1 4 √73 or x= −7 4 + −1 4 √73

please mark me as the brainliest:)

8 0

4 years ago

Read 2 more answers

A cube-shaped box has a volume of 64 cubic inches.

Naddik [55]

LxWxH
4x4x4= 64 cubic inches
So the answer is 4 cubes

6 0

3 years ago

If you're given the points:

ohaa [14]

The answer is C look at the first number is y coordinate position (x,y) and Y1=10 and Y2=9

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3 years ago

2. Inflation is at a rate of 7% per year. Evan's favorite bread now costs $1.79. What did it cost 10 years ago? How long

zavuch27 [327]

Answer:

It cost $0.91 10 years ago.

It takes 10.24 years for the cost of bread to double.

Step-by-step explanation:

The equation for the price of bread after t years has the following format:

$P(t) = P(0)(1+r)^{t}$

In which P(0) is the current price, and r is the inflation rate, as a decimal.

If we want to find the price for example, 10 years ago, we find P(-10).

Inflation is at a rate of 7% per year. Evan's favorite bread now costs $1.79.

This means that $r = 0.07, P(0) = 1.79$ . So

$P(t) = P(0)(1+r)^{t}$

$P(t) = 1.79(1+0.07)^{t}$

$P(t) = 1.79(1.07)^{t}$

What did it cost 10 years ago?

$P(-10) = 1.79(1.07)^{-10} = 0.91$

It cost $0.91 10 years ago.

How long before the cost of the bread doubles?

This is t for which P(t) = 2P(0) = 2*1.79. So

$P(t) = 1.79(1.07)^{t}$

$2*1.79 = 1.79(1.07)^{t}$

$(1.07)^{t} = 2$

$\log{(1.07)^{t}} = \log{2}$

$t\log{1.07} = \log{2}$

$t = \frac{\log{2}}{\log{1.07}}$

$t = 10.24$

It takes 10.24 years for the cost of bread to double.

7 0

3 years ago