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Lostsunrise [7]
1 year ago
5

Use the properties of 30-60-90 and 45-45-90 triangles to solve for x in each of the problems below. Then decode the secret messa

ge by matching the answer with the corresponding letter/symbol from the exercises.

Mathematics
1 answer:
murzikaleks [220]1 year ago
5 0

The trigonometric function gives the ratio of different sides of a right-angle triangle. The given problems can be solved as given below.

<h3>What are Trigonometric functions?</h3>

The trigonometric function gives the ratio of different sides of a right-angle triangle.

\rm Sin \theta=\dfrac{Perpendicular}{Hypotenuse}\\\\\\Cos \theta=\dfrac{Base}{Hypotenuse}\\\\\\Tan \theta=\dfrac{Perpendicular}{Base}\\\\\\Cosec \theta=\dfrac{Hypotenuse}{Perpendicular}\\\\\\Sec \theta=\dfrac{Hypotenuse}{Base}\\\\\\Cot \theta=\dfrac{Base}{Perpendicular}\\\\\\

where perpendicular is the side of the triangle which is opposite to the angle, and the hypotenuse is the longest side of the triangle which is opposite to the 90° angle.

1st.) x = 5 /Sin(30°)

x = 10

!) sin(45°) = 4/x

x = 4/sin(45°)

x = 4√2

I) Cos(45°) = √3 / x

x = √3 / Cos(45°)

x = √6

E) Tan(60°) = 3√3 / x

x = 3√3 / 3

W) For isosceles right-triangle, the angle made by the legs and the hypotenuse is always 45°.

x = 45°

N) x² + x² = (7√2)²

x = 7

V) Tan(60°) = 7 / x

x = 7√3/3

K) x² + x² = (9)²

x = 9/√2

Y) Sin(60°) = 7√3/x

x = 14

M) Sin(30°) = x/11

x = 11/2

T) Sin(45°) = x/√10

x = √5

A) x + 2x + 90° = 180°

x = 30°

O) Sin(45°) = √2 / x

x = 2

R) Tan(30°) = x / 4

x = 4/√3 = 4√3 / 3

S) Sin(60°) = x / (10/3)

x = 5√3 / 3

Learn more about Trigonometric functions:

brainly.com/question/6904750

#SPJ1

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Simplify this expression <br> 7z+5+6z-9
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7z + 5 + 6z - 9  (Add 7z and 6z, subtract 9 from 5)

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2 years ago
Suppose that the store manager of a small rural pharmacy is doing a linear regression of daily sales of over-the-counter (OTC) d
Doss [256]

Answer:

3.83

Step-by-step explanation:

Mean of x = Σx / n

Mean of x = (14 + 19 + 13 + 6 + 9) / 5 = 12.2

Sum of square (SS) :

(14-12.2)^2 + (19-12.2)^2 + (13-12.2)^2 + (6-12.2)^2 + (9-12.2)^2 = 98.8

Mean of y = Σy / n

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Σ(y - ybar)² = (101-61.2)^2 + (89-61.2)^2 + (48-61.2)^2 + (21-61.2)^2 + (47-61.2)^2 = 4348.8

df = n - 2 = 5 - 2 = 3

Σ(y - ybar)² / df = 4348.8 / 3 = 1449.6

√(Σ(y - ybar)² / df) = √1449.6 = 38.074

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4 0
2 years ago
2x3 + x2 + 7x - 6)-(- 2x + 10x + 10x+9)​
AVprozaik [17]

Answer:

2x³ + x² - 11x - 15

Step-by-step explanation:

Step 1: Write out expression

2x³ + x² + 7x - 6 - (-2x + 10x + 10x + 9)

Step 2: Distribute negative

2x³ + x² + 7x - 6 + 2x - 10x - 10x - 9

Step 3: Combine like terms (x)

2x³ + x² + 9x - 10x - 10x - 9 - 6

2x³ + x² - x - 10x - 9 - 6

2x³ + x² - 11x - 9 - 6

Step 4: Combine like terms (constants)

2x³ + x² - 11x - 15

5 0
3 years ago
A manufacturer of college textbooks is interested in estimating the strength of the bindings produced by a particular binding ma
IrinaVladis [17]

Answer:

538 books should be tested.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.99}{2} = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.005 = 0.995, so z = 2.575

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

How many books should be tested to estimate the average force required to break the binding to within 0.08 lb with 99% confidence?

n books should be tested.

n is found when M = 0.08

We have that \sigma = 0.72

M = z*\frac{\sigma}{\sqrt{n}}

0.08 = 2.575*\frac{0.72}{\sqrt{n}}

0.08\sqrt{n} = 2.575*0.72

\sqrt{n} = \frac{2.575*0.72}{0.08}

(\sqrt{n})^{2} = (\frac{2.575*0.72}{0.08})^{2}

n = 537.1

Rounding up

538 books should be tested.

6 0
2 years ago
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