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IgorLugansk [536]
3 years ago
9

The length of a rectangle is 5 in. more than 3 times its width. The quadratic function f(x) = x(3x + 5) represents the area of t

he rectangle in terms of its width. What is a reasonable domain of the function?
A) real numbers
B) all real numbers less than 50
C) all real numbers less than zero
D) all real numbers greater than zero
Mathematics
2 answers:
Hunter-Best [27]3 years ago
8 0

Answer:

D) all real numbers greater than zero

Step-by-step explanation:

The area of the rectangle must be greater than zero. Because an area equal to zero or a negative area wouldn't make any sense. So let's write the inequalities in order to find the correct domain:

f(x)=x(3x+5)>0

Split in two equations:

x>0\hspace{32}(1)\\\\3x+5>0\hspace{10}(2)

From (1) we can determine directly that 5 must be greater than zero.

Now, for equation (2):

3x+5>0\\\\3x>-5\\\\x>-\frac{5}{3}

So, x can also take negative values less than -5/3, for example, let's evaluate the area for x=-2:

f(-2)=-2(3(-2)+5)=-2(-6+5)=-2(-1)=2

This would make sense for the area, however it wouldn't make sense for the side measurements. Never heard about of -10 ft for example.

Therefore the  domain of the function which make sense in this case is all real numbers greater than zero.

saveliy_v [14]3 years ago
5 0
F(x)=x(3x+5)
or
f(x)=3x²+5x
Here the domain in general is: -∞<x<∞
But the length of the rectangle cannot be negative, therefore the domain is all real numbers greater than zero.

Option D is correct.


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0.005 ___ 0.05<br>&lt;<br>&gt;<br>=<br><br>thanks :&gt;​
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<h2><em>hope </em><em>it</em><em> helps</em><em>!</em></h2>

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