It has exactly one solution.
If you graph both of these equations on desmos, you will see that they only cross once. Therefore you only have one solution
Answer:
x = 41°, y = 139°
Step-by-step explanation:
The given parameters are;
Line <em>m</em> is parallel to line <em>n</em> and lines <em>m</em> and <em>n</em> have a common transversal
The corresponding angles formed by the common transversal to the two parallel lines are 41° on line <em>m</em> and <em>x°</em> on line <em>n</em>
Therefore, x° = 41° by corresponding angles formed between on two parallel lines by a common transversal are equal
x° and y° are linear pair angles and they are, supplementary
∴ x° + y° = 180°
∴ x° + y° = 41° + y° = 180°
y° = 180° - 41° = 139°
y° = 139°.
Answer:
(
−
5
)
(
−
4
)
Step-by-step explanation:
Not 100 percent sure
Step-by-step explanation:
In figure:
∠PRT+∠RTP+∠TPR=180
O
(angle sum property of triangle)
⇒x+(180
O
−∠RTQ)+60
O
=180
O
(linear pair)
⇒x+(180
O
−97
0
)+60
o
=180
O
⇒x=31
o
Now, ∠PRT+∠TRQ+∠QRS=180
O
(angle of straight line)
⇒x+48
o
+y=180
O
⇒31
o
+48
o
+y=180
O
⇒y=101
0
Answer:
C
Step-by-step explanation: