1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vika [28.1K]
2 years ago
15

What is the square root of -1?

Mathematics
1 answer:
Morgarella [4.7K]2 years ago
6 0

Answer:

It has no square root because it's negative.

Step-by-step explanation:

You might be interested in
Consider the parabola given by the equation: f(x) = 4x² - 6x - 8 Find the following for this parabola: A) The vertex: Preview B)
jeyben [28]

Answer:

The vertex: (\frac{3}{4},-\frac{41}{4} )

The vertical intercept is: y=-8

The coordinates of the two intercepts of the parabola are (\frac{3+\sqrt{41} }{4} , 0) and (\frac{3-\sqrt{41} }{4} , 0)

Step-by-step explanation:

To find the vertex of the parabola 4x^2-6x-8 you need to:

1. Find the coefficients <em>a</em>, <em>b</em>, and <em>c </em>of the parabola equation

<em>a=4, b=-6, \:and \:c=-8</em>

2. You can apply this formula to find x-coordinate of the vertex

x=-\frac{b}{2a}, so

x=-\frac{-6}{2\cdot 4}\\x=\frac{3}{4}

3. To find the y-coordinate of the vertex you use the parabola equation and x-coordinate of the vertex (f(-\frac{b}{2a})=a(-\frac{b}{2a})^2+b(-\frac{b}{2a})+c)

f(-\frac{b}{2a})=a(-\frac{b}{2a})^2+b(-\frac{b}{2a})+c\\f(\frac{3}{4})=4\cdot (\frac{3}{4})^2-6\cdot (\frac{3}{4})-8\\y=\frac{-41}{4}

To find the vertical intercept you need to evaluate x = 0 into the parabola equation

f(x)=4x^2-6x-8\\f(0)=4(0)^2-6\cdot 0-0\\f(0)=-8

To find the coordinates of the two intercepts of the parabola you need to solve the parabola by completing the square

\mathrm{Add\:}8\mathrm{\:to\:both\:sides}

x^2-6x-8+8=0+8

\mathrm{Simplify}

4x^2-6x=8

\mathrm{Divide\:both\:sides\:by\:}4

\frac{4x^2-6x}{4}=\frac{8}{4}\\x^2-\frac{3x}{2}=2

\mathrm{Write\:equation\:in\:the\:form:\:\:}x^2+2ax+a^2=\left(x+a\right)^2

x^2-\frac{3x}{2}+\left(-\frac{3}{4}\right)^2=2+\left(-\frac{3}{4}\right)^2\\x^2-\frac{3x}{2}+\left(-\frac{3}{4}\right)^2=\frac{41}{16}

\left(x-\frac{3}{4}\right)^2=\frac{41}{16}

\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}

x_1=\frac{\sqrt{41}+3}{4},\:x_2=\frac{-\sqrt{41}+3}{4}

4 0
3 years ago
Jenny earned 92 of a possible 120 points on a test. She lost 4 points for each
Kryger [21]
Jenny missed 7 problems on the 120 point test
7 0
3 years ago
Read 2 more answers
Helppppppppppppppppppppppp​
Vikentia [17]

Step-by-step explanation:

area of trapezoid=(a+b)×h divided by 2

=(9+19)×4 divided by2

=28×4 divided by2

=112 divided by 2

=56m square

6 0
2 years ago
Carson graphs the line y= -1/4 + 4. Then Riley's graphs the line perpendicular to the line Carson's line through the point (8,10
gizmo_the_mogwai [7]

Answer:

4/1 or 4

Step-by-step explanation:

when graphing perpendicular lines, the slopes are reciprocals of eachother

5 0
2 years ago
Suppose that you are in a class of 33 students and it is assumed that approximately 15% of the population is left-handed. (give
AysviL [449]
15% of 33 =

= 15% * 33

= 0.15 * 33

= 4.950 students in that class are left-handed
3 0
3 years ago
Other questions:
  • Assume that each of the n trials is independent and that pis
    8·1 answer
  • Please help please help
    14·2 answers
  • I'll mark you brainliest for the right answer and 15 POINTS!!!
    13·2 answers
  • Allyson can pay for her gym membership on a monthly​ basis, but if she pays for an entire​ year's membership in​ advance, she'll
    8·1 answer
  • If right I’ll mark brainiest
    13·1 answer
  • 29/1000
    12·1 answer
  • How many vehicles are at Nam's Gas Station?
    11·2 answers
  • Combine like terms in the following expression: 2x+5y+7t+4p-x-4t+3y-4t-3p
    11·1 answer
  • Hi, can someone help me with this question?
    9·2 answers
  • Please check the image below for more info on the question
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!