<h2>
Explanation:</h2>
We have the function:
The vertical asymptote can be found when the denominator equal zero, therefore:
So the vertical asymptote occur at 
1.x2x
+x.4x7
5.036 (sorry the underline function is no longer available)
In the thousandth column we have x +7 and we wind up with a 6 in that column.
Since 7 is already more than 6 that means the only number that will work is 9 and there will be a carry of one into the hundredths place.
1.x29
+x.4x7
5.036
Now let's look at the tenths column. 2 becomes 3 in the answer and there was a carry of 1 from the thousandths so the other number must be a zero
1.x29
+ x.407
5.036 Now I need a number that goes with 4 and puts a zero in the answer.
That number has to be 6 and does cause a carry of one into the ones
place
1.629
+x.407
5.036
Finally (remembering there is a carry of one in the ones place) I have two (1 + 1 carried) toward my five in the answer. I need three more.
Here is the final example:
1.629
+3.407
5.036
Answer:
2.304, 2.34, 2.5, 3.21
Step-by-step explanation:
1. Look at the digit in the ones place. See how they are all 2s except for one 3? Well, now we know the one with the 3 must be the greatest, since 3>2.
2. Next, look at the digit in the tenths place. We have a 3, 3, and a 5. Since 5 > 3, we know thar 2.5 is the second greatest.
3. Last, look at the hundreths place. We have a 0 and a 4. Since 4 > 0, that means 2.34 is the third greatest.
4. Since this is from least to greatest, put 2.304 first and the others as follows in the answer. Hope this helps.
Uh idek but i think the relationship is that x is plus 1 every time and y is plus 4 every time
Answer:
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Step-by-step explanation:
its invisible ehjsidhsjsisshwnsiduwhjsdidjensndirh
