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lisov135 [29]
2 years ago
9

#280 at the

Mathematics
1 answer:
Korvikt [17]2 years ago
4 0

Based on the amount that Nader can pay per month, and the interest rate as well as the period, the amount he could spend if the rate was annual is $8,385.33.

<h3 /><h3>How much could Nader spend on the car?</h3>

If Nader can pay $280 per month, the amount he can pay per year i:

= 280 x 12

= $3,360

The amount that he can spend on the car is the present value of these yearly payments:

= 3,360 x (1 - (1 + 9.8%)⁻³) / 9.8%

= 3,360 x 2.49563439768461

= $8,385.33

Find out more on the present value of periodic payments at brainly.com/question/17244776.

#SPJ1

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What is the slope of a line perpendicular to the line whose equation is 18x+15y=180.
professor190 [17]

18x + 15y = 180

15y = -18X + 180

Y= -18/15x + 12

4 0
4 years ago
Which function in vertex form is equivalent to f(x)=4+x^2-2x
morpeh [17]
F(x)=4-2x+x^2
=4-1+1-x-x+x^2
=3+(1-x) - x(1-x)
= 3+(1-x) (1-x)
= 3 + (1 - x)^2
f(x) = (1 - x)^2 + 3
5 0
4 years ago
A new washing machine used 3 2/4 gallons of water per full load to clean cloths. If John washed 2 2/3 loads of clothes, how many
kumpel [21]
We know that
3 2/4  -------------> is (3*4+2)/4--------> 14/4-------> 7/2
2 2/3 --------------> is (2*3+2)/3--------> 8/3

if a new washing machine used 7/2 gallons of water ------------> one full load <span>cloths
</span> X gallons of water------------------------------------------------------> 8/3 of load cloths<span>
X=(8/3)*(7/2)---------> X=56/6------->28/3 gallons of water
28/3--------> 9 1/3 gallons of water

the answer is
 </span>9 1/3 gallons of water
7 0
3 years ago
Oliver is performing an experiment by spinning a metal weight around on the end of a nylon thread. How far does the metal weight
skad [1K]

Answer:

27.7m

Step-by-step explanation:

Step 1

We find the Circumference of the nylon thread.

The formula = 2πr

The diameter of the thread = 0.88m

Radius = Diameter/2

= 0.88m/2

= 0.44m

Circumference = 2 × π × 0.44m

= 2.7646015352m

Approximately = 2.765m

Step 2

We calculate the distance

Number of revolutions = 10

Therefore, the Distance or how far the metal weight can travel =

Circumference of the wheel × Number of revolutions

= 2.765m × 10

= 27.65m

Approximately to 1 decimal place = 27.7m

8 0
3 years ago
Write an equation fo nth term of the given arithmetic sequence 7,13,19,25,...
Leya [2.2K]

Answer:

The nth term for the given sequence can be written as:

a_n=6\,n+1

Step-by-step explanation:

Notice that this arithmetic sequence is created by adding to each term a common difference of 6 units:

7 + 6 = 13

13 + 6 = 19

19 + 6 = 25

Then, using the general expression for the nth term of an arithmetic sequence of first term "a_1"  and common difference "<em>d</em>" we can write the nth term as:

a_n=a_1+(n-1)\,d

which in this case translates as:

a_n=a_1+(n-1)\,d= 7\,+(n-1)\,6=7+6\,n-6=6\,n+1

8 0
3 years ago
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