The answer is A = P²/16
The perimeter P of a square is sum of its sides s: P = s + s + s + s = 4s
The area A of a square with side s is: A = s * s = s²
Step 1: Solve s from the formula for the perimeter.
Step 2: substitute s from the formula for the perimeter into the formula for the area.
Step 1:
P = 4s
s = P/4
Step 2:
A = s²
s = P/4
A = (P/4)²
A = P²/4²
A = P²/16
This would be 32 Dime totaling $3.20 an 34 nickles for 1.70
34*5+170 aka 1.70
32*=320 aka 3.20
3.20+1.70+4.90
<span>You have the following inequality given in the problem shown above:
(x^2-1)/(x^2+5x+4)</span>≤<span>0
1. To solve it, you must factor it and then you must make the study of the signs.
2. Once you do the proccedure mentioned above, you obtain the following solutions:
-4<x<-1 -1<x</span>
≤<span>
1
3. You can graph the inaquality given in the problem, as you can see in the figure attached.</span>
Hey There @Bre18016,
The answer is 
The greatest value of 2,463.9051 would be the thousands place (2) simply as it is the biggest number out of the other places.
For instance, if we had the number 300, 3 would be the greatest value.
Or let's say we had 10,000 the 1 would be the greatest value.
Furthermore, you could look at the first digit in the entire number to deter mine the greatest value.
Given :
On the first day of ticket sales the school sold 10 senior tickets and 1 child ticket for a total of $85 .
The school took in $75 on the second day by selling 5 senior citizens tickets and 7 child tickets.
To Find :
The price of a senior ticket and the price of a child ticket.
Solution :
Let, price of senior ticket and child ticket is x and y respectively.
Mathematical equation of condition 1 :
10x + y = 85 ...1)
Mathematical equation of condition 2 :
5x + 7y = 75 ...2)
Solving equation 1 and 2, we get :
2(2) - (1) :
2( 5x + 7y - 75 ) - ( 10x +y - 85 ) = 0
10x + 14y - 150 - 10x - y + 85 = 0
13y = 65
y = 5
10x - 5 = 85
x = 8
Therefore, price of a senior ticket and the price of a child ticket $8 and $5.
Hence, this is the required solution.