1) For a quadratic equation, we'll have two answers typically. We're looking for two numbers that when multiplied give -64, and when added give -12. This is a bit of trial and error, but you go about it by systematically factoring -64 in all possible combinations: 64=-2*32=2*-32=-4*16=4*-16=-8*8. Of these, I can 'see' that I can make -12 with 4 and -16. So the factorization of the equation becomes:
(x-16)(x+4)=0, so x=16 or x=-4.
Answers B and D are correct.
For (2), same trick applies. Rewrite as x²-8x-48=0. Factor as (x+4)(x-12)=0 because 4*-12=-48 and 4-12=-8. The other solution is x=12.
Answer: it should be 28
Step-by-step explanation: because the way the other problems are solved is the right side of the triangle times the bottom and then adding the left side of the triangle, ( 9x8+7=79 ) ( 5x5+5=30) so to get the answer you’d just multiply 24x3= 72 , then subtract 100-72= 28
Step-by-step explanation:
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Number of tests made =x
Verzon C(x) = 45 + 0.1x => 45+0.1*1200 =165
AT & T C(y) = 30 + 0.13x=> 30 + 0.13*1200=186
For 1200 texts C(x) is less than C(y)
If the costs are to be the same then
45 + 0.1x = 30 + 0.13x
15=0.03x
15/0.03= x
500=x
500 texts
