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Arlecino [84]
1 year ago
5

How do you Calculate the mean,median and mode in grouped data.

Mathematics
1 answer:
Dmitrij [34]1 year ago
7 0

Answer:

The mean:

data: 3,6,9,10

You first add all of the numbers together.

3+6+9+10= 28

There 4 numbers in the data set, so you divide 4 by the sum of all of the numbers.

28/4= 7

So the mean is 7.

The median:

data: 3,6,9,10

first put all of the numbers in numerical order.

3,6,9,10

Then you find the middle number in the data set.

3,6,(the middle number here),9,10

to find the middle number, do the mean of 6 and 9

The mean of 6 and 9 is 7.5

So, 7.5 is the median

another example: 3,4,7,9,13

The middle number is 7

so 7 is the median

The mode:

data: 3,6,9,10

The mode is the number that is repeated the most

in this data, there is no mode.

but in this data: 4,4,6,9,11

4 is the mode because it was repeated the most

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Help me on this question! Jake can carry 6 1/4 pounds of wood in from the barn.His father can carry 1 5/7 times as much as jake.
ioda

\text{ Jake father can carry } 10\frac{5}{7} \text{ or } \frac{75}{7} \text{ pounds }

<em><u>Solution:</u></em>

From given question,

Number of pounds Jake carry = 6\frac{1}{4} \text{ pounds }

Number of pounds his father carry is 1\frac{5}{7} times as much as jake

To find: Number of pounds Jake father can carry

<em><u>Convert the mixed fractions to improper fractions</u></em>

Multiply the whole number part by the fraction's denominator.

Add that to the numerator.

Then write the result on top of the denominator

\rightarrow 6\frac{1}{4} = \frac{4 \times 6+1}{4} = \frac{25}{4}\\\\\rightarrow 1\frac{5}{7} = \frac{7 \times 1+5}{7} = \frac{12}{7}

<em><u>Then according to question,</u></em>

\text{Pounds father carry } = \frac{12}{7} \text{ times the pounds jake carry }\\\\\text{Pounds father carry } = \frac{12}{7} \times \frac{25}{4}\\\\\text{Pounds father carry } = \frac{75}{7}\\\\\text{In terms of mixed fractions, }\\\\\text{Pounds father carry } = \frac{75}{7} = 10\frac{5}{7}

\text{ Thus, Jake father can carry } 10\frac{5}{7} \text{ or } \frac{75}{7} \text{ pounds }

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