Answer:
[(x + 6), (y + 1)]
Step-by-step explanation:
Vertices of the quadrilateral ABCD are,
A → (-5, 2)
B → (-3, 4)
C → (-2, 4)
D → (-1, 2)
By reflecting the given quadrilateral ABCD across x-axis to form the image quadrilateral A'B'C'D',
Rule for the reflection of a point across x-axis is,
(x, y) → (x , -y)
Coordinates of the image point A' will be,
A(-5, 2) → A'(-5, -2)
From the picture attached, point E is obtained by translation of point A'.
Rule for the translation of a point by h units right and k units up,
A'(x+h, y+k) → E(x', y')
By this rule,
A'(-5 + h, -2 + k) → E(1, -1)
By comparing coordinates of A' and E,
-5 + h = 1
h = 6
-2 + k = -1
k = 1
That means
Rule for the translation will be,
[(x + 6), (y + 1)]
Answer:
D. y = -5/7x + 5
Step-by-step explanation:
5x + 7y = 35
-5x -5x
7y = 35 - 5x
/7 /7 /7
y = 35/7 - 5/7 x
y = 5 - 5/7x
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The line GH bisects The triangle FGI meaning it divides it into two equal parts <em>(that is the definition if bisection); </em>therefore, the angles FGH and HGI are equal:
Now let us add 2 to both sides gives
subtracting 4x from both sides gives
Hence, x = 11.
The measure of FGH is
(B)
The measure of HGI is
(C)
The measure of FGI is the sum of HGI and FGH:
<em />
Answer:
3 sqrt(3) =x
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
cos theta = adj / hyp
cos 30 = x/6
6 cos 30 = x
6 ( sqrt(3)/2) = x
3 sqrt(3) =x
