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artcher [175]
2 years ago
14

When proving the product, quotient, or power rule of logarithms, various properties of logarithms and exponents must be used.

Mathematics
1 answer:
Bingel [31]2 years ago
7 0

When proving the properties of logarithms when exponents must be used, the property that is used in all of these is D. log_{b} (b^y) = y

<h3>What property is used in proving the properties of logarithms?</h3>

When proving any property of logarithms that have to do with exponents, one property that should always be used is  log_{b} (b^y) = y.

Expressing y as a product of log_{b} (b^y) is the most basic property of using exponents on logs because it has both product, quotient, and power rules of logarithms.

Find out more on logarithmic properties at brainly.com/question/15263375.

#SPJ1

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Wittaler [7]

Answer: B/The second answer

Step-by-step explanation:

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3 years ago
Note: Enter your answer and show all the steps that you use to solve this problem in the space provided. Annika borrowed a book
ZanzabumX [31]

Answer:

Annika was 14 days late with her book.

Step-by-step explanation:

The first four days would cost Annika 1.0 dollar (4x0.25), then we need to divide the rest of the ammount by 0.30 to calculate for how many days she paid the 0.30 dollar fine.

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Therefore, Annika was 4 +10 = 14 days late with her book.

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3 years ago
Find the solution to the system of equations. You can use the interactive graph below to find the solution. y=-4x-3 y=-2x+1 x= y
Mama L [17]

Answer:

(-2, 5)

Step-by-step explanation:

I will assume that your system is

y = -4x - 3

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combining these two equations eliminates x temporarily:

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Substituting 5 for y in the second equation, we get:

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3 years ago
Which best describes how to add 9.73 and 21.6
Marta_Voda [28]

Answer:

Step-by-step explanation:

9.73

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8 0
3 years ago
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Karo-lina-s [1.5K]

Answer:

Yes

Step-by-step explanation:

The ordered pairs are (6,72) (8,96) (5.5, 66) (9,108) (7,84).

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So, per hour Jerry earns 12 dollars.

Hence, the ordered pairs are relation.

8 0
3 years ago
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