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Akimi4 [234]
3 years ago
10

Please help me this is due today

Mathematics
1 answer:
Evgen [1.6K]3 years ago
6 0
Split the room into 2 rectangles 
area =  5*4 + 3*3  = 29 sq ft

So the cost is 29*8 =  $232
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A rectangular flower garden in Samantha's backyard has 220 feet around its edge. The width of the garden is 50 feet. What is the
Ede4ka [16]

Answer: 60 ft

Step-by-step explanation:

Given

The perimeter of the garden is 220\ ft

The width of the garden is 50\ ft

Suppose the length of the garden is x

Perimeter is the sum of the lengths of the sides

\Rightarrow 220=2(x+50)\\\Rightarrow 110=x+50\\\Rightarrow x=60\ ft

So, the length of the garden is 60\ ft

4 0
3 years ago
What is 0.66% of 9,500 is
Hatshy [7]

Answer:

62.7

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
What the answer of a/7 = -15
IceJOKER [234]
The answer would be -105. If you multiply 7 x -15 it would give you -105 and then you would have to divide -105 by 7 and its equal to -15.

7 0
3 years ago
Given:quadrillateral ABCD inscribed in a circle
son4ous [18]

Answer:

Step-by-step explanation:

Given: quadrilateral ABCD inscribed in a circle

To Prove:

1. ∠A and ∠C are supplementary.

2. ∠B and ∠D are supplementary.

Construction : Join AC and BD.

Proof: As, angle in same segment of circle are equal.Considering AB, BC, CD and DA as Segments, which are inside the circle,

∠1=∠2-----(1)

∠3=∠4-----(2)

∠5=∠6-------(3)

∠7=∠8------(4)

Also, sum of angles of quadrilateral is 360°.

⇒∠A+∠B+∠C+∠D=360°

→→∠1+∠2+∠3+∠4+∠5+∠6+∠7+∠8=360°→→→using 1,2,3,and 4

→→→2∠1+2∠4+2∠6+2∠8=360°

→→→→2( ∠1 +∠6) +2(∠4+∠8)=360°⇒Dividing both sides by 2,

→→→∠B + ∠D=180°as, ∠1 +∠6=∠B , ∠4+∠8=∠B------(A)

As, ∠A+∠B+∠C+∠D=360°

∠A+∠C+180°=360°

∠A+∠C=360°-180°------Using A

∠A+∠C=180°

Hence proved.

credit: someone else

5 0
3 years ago
I need help asapp!!!!!!!
labwork [276]

Answer:

Step-by-step explanation:

As per midsegment theorem of a trapezoid,

Segment joining the midpoints of the legs of the of the trapezoid is parallel to the bases and measure half of their sum.

Length of midsegment = \frac{1}{2}(b_1+b_2)

3). MN = \frac{1}{2}(18+10)

           = 14

4). MN = \frac{1}{2}(57+76)

           = 66.5

5). MN = \frac{1}{2}(AB+DC)

    7 = \frac{1}{2}(AB+10)

    14 = AB + 10

    AB = 14 - 10

    AB = 4

6). 15 = \frac{1}{2}[(3x+2)+(2x-2)]

    30 = 5x

     x = 6

4 0
2 years ago
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