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3 years ago

Find the volume of a CUBE if its side length is : x+2 in polynomial form

1 answer:

8 0

Volume = Length x Length x Length

Volume :

(x + 2) (x + 2) (x + 2)

= (x² + 4x + 4)(x + 2)

= x³ + 2x² + 4x² + 8x + 4x + 8

= x³ + 6x² + 12x + 8

Answer: x³ + 6x² + 12x + 8

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Drina wrote the system of linear equations below.

zalisa [80]

Answer:

Option c, A square matrix

Step-by-step explanation:

Given system of linear equations are

$3x-2y=-2\hfill(1)$

$7x+3y=26\hfill(2)$

$-x-11y=46\hfill(3)$

Now to find the type of matrix can be formed by using this system

of equations

From the given system of linear equations we can form a matrix

Let A be a matrix

A matrix can be written by

A=co-efficient of x of 1st linear equation co-efficient of y of 1st linear equation constant of 1st terms linear equation

co-efficient of x of 2st linear equation co-efficient of y of 2st linear equation constant of 2st terms linear equation

co-efficient of x of 3st linear equation co-efficient of y of 3st linear equation constant of 3st terms linear equation $3\times 3$

which is a $3\times 3$ matrix.

Therefore A can be written as

A= $\left[\begin{array}{lll}3&-2&-2\\7&3&26\\-1&-11&46\end{array}\right] 3\times 3$

Matrix "A" is a $3\times3$ matrix so that it has 3 rows and 3 columns

A square matrix has equal rows and equal columns

Since matrix "A" has equal rows and columns Therefore it must be a square matrix

Therefore the given system of linear equation forms a square matrix

7 0

3 years ago

Read 2 more answers

How do you work out (7x+3)(7x-3)

spin [16.1K]

We can solve this using the FOIL method.

= (7x + 3)(7x - 3)

= (7x * 7x) + (7x * -3) + (3 * 7x) + (3 * -3)

= 49x - 21x + 21x - 9

= 49x - 9

Hope This Helped! Good Luck!

7 0

3 years ago

The equation giving a family of ellipsoids is u = (x^2)/(a^2) + (y^2)/(b^2) + (z^2)/(c^2) . Find the unit vector normal to each

Fynjy0 [20]

Answer:

$\hat{n}\ =\ \ \dfrac{\dfrac{x}{a^2}\hat{i}+\ \dfrac{y}{b^2}\hat{j}+\ \dfrac{z}{c^2}\hat{k}}{\sqrt{(\dfrac{x}{a^2})^2+(\dfrac{y}{b^2})^2+(\dfrac{z}{c^2})^2}}$

Step-by-step explanation:

Given equation of ellipsoids,

$u\ =\ \dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}+\dfrac{z^2}{c^2}$

The vector normal to the given equation of ellipsoid will be given by

$\vec{n}\ =\textrm{gradient of u}$

$=\bigtriangledown u$

$=\ (\dfrac{\partial{}}{\partial{x}}\hat{i}+ \dfrac{\partial{}}{\partial{y}}\hat{j}+ \dfrac{\partial{}}{\partial{z}}\hat{k})(\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}+\dfrac{z^2}{c^2})$

$=\ \dfrac{\partial{(\dfrac{x^2}{a^2})}}{\partial{x}}\hat{i}+\dfrac{\partial{(\dfrac{y^2}{b^2})}}{\partial{y}}\hat{j}+\dfrac{\partial{(\dfrac{z^2}{c^2})}}{\partial{z}}\hat{k}$

$=\ \dfrac{2x}{a^2}\hat{i}+\ \dfrac{2y}{b^2}\hat{j}+\ \dfrac{2z}{c^2}\hat{k}$

Hence, the unit normal vector can be given by,

$\hat{n}\ =\ \dfrac{\vec{n}}{\left|\vec{n}\right|}$

$=\ \dfrac{\dfrac{2x}{a^2}\hat{i}+\ \dfrac{2y}{b^2}\hat{j}+\ \dfrac{2z}{c^2}\hat{k}}{\sqrt{(\dfrac{2x}{a^2})^2+(\dfrac{2y}{b^2})^2+(\dfrac{2z}{c^2})^2}}$

$=\ \dfrac{\dfrac{x}{a^2}\hat{i}+\ \dfrac{y}{b^2}\hat{j}+\ \dfrac{z}{c^2}\hat{k}}{\sqrt{(\dfrac{x}{a^2})^2+(\dfrac{y}{b^2})^2+(\dfrac{z}{c^2})^2}}$

Hence, the unit vector normal to each point of the given ellipsoid surface is

$\hat{n}\ =\ \ \dfrac{\dfrac{x}{a^2}\hat{i}+\ \dfrac{y}{b^2}\hat{j}+\ \dfrac{z}{c^2}\hat{k}}{\sqrt{(\dfrac{x}{a^2})^2+(\dfrac{y}{b^2})^2+(\dfrac{z}{c^2})^2}}$

3 0

3 years ago

Write the equation of the line through the indicated point with the indicated slope. write the final answer in the form y equals

Assoli18 [71]

y = - 4x + 13

slope = -4

y-intercept = 13

8 0

3 years ago

Please can someone help me with INTERIM CHECKPOINT Math problems

gogolik [260]

The answer will be -32

8 0

3 years ago