<span>an animal whose mouth develops from a second opening in the early embryo, opposite to the initial opening blastopore of the rudimentary gut. Chordates and echinoderms are deuterostomes.</span>
I believe it is during the day A
Correct question:
if a nondisjunction occurs at anaphase I of the first meiotic division, what will the proportion of abnormal gametes (for the chromosomes involved in the nondisjunction)?
Answer:
100%
Explanation:
Nondisjunction at meiosis-I means that two homologous chromosomes of at least one homologous pair fail to separate from each other during anaphase-I. This would result in the formation of one cell with one extra chromosome and the other with one less chromosome by the end of meiosis-I. Meiosis-II in these two cells would maintain this chromosome number in the daughter cells. Therefore, out of the total four gametes formed by the end of the meiosis, two would have one extra chromosome and would be denoted as "n+1". The rest of the two gametes would have one less chromosome and would be denoted as "n-1".
Answer:
See the answer below
Explanation:
The central dogma gives a description of how genetic information travels in biological cells from DNAs to proteins. DNAs are first transcribed into messenger RNAs in a process known as transcription and the resulting mRNAs are used in the synthesis of proteins in a process known as translation.
In eukaryotic cells, transcription process happens within the confines of the nucleus because the genetic material in the form of DNAs are always located in the nucleus. Thereafter, the mRNAs generated from transcription are transported to the cytoplasm of the cell where they become translated into proteins.
Hence;
- <em>T</em><em>ranscription</em><em> happens in the </em><em>nucleus</em><em> of the cell.</em>
- <em>Translation </em><em>happens in the </em><em>cytoplasm</em><em> of the cell.</em>
Carbon dioxide is a reactant and oxygen and glucose are products.
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