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tresset_1 [31]
4 years ago
12

Which equation is satisfied by all of the plotted points?

Mathematics
1 answer:
Brums [2.3K]4 years ago
3 0
The equation that is satisfied by all of the plotted points would be F. 3x because the y-intercept is at 0 so there wouldn't be one and the graph has a ratio of 3/1 so for every 3 numbers the line moves up it moves 1 space to the right, also indicating that it is positive.
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Find the sum of the positive integers less than 200 which are not multiples of 4 and 7​
taurus [48]

Answer:

12942 is the sum of positive integers between 1 (inclusive) and 199 (inclusive) that are not multiples of 4 and not multiples 7.

Step-by-step explanation:

For an arithmetic series with:

  • a_1 as the first term,
  • a_n as the last term, and
  • d as the common difference,

there would be \displaystyle \left(\frac{a_n - a_1}{d} + 1\right) terms, where as the sum would be \displaystyle \frac{1}{2}\, \displaystyle \underbrace{\left(\frac{a_n - a_1}{d} + 1\right)}_\text{number of terms}\, (a_1 + a_n).

Positive integers between 1 (inclusive) and 199 (inclusive) include:

1,\, 2,\, \dots,\, 199.

The common difference of this arithmetic series is 1. There would be (199 - 1) + 1 = 199 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times ((199 - 1) + 1) \times (1 + 199) = 19900 \end{aligned}.

Similarly, positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 4 include:

4,\, 8,\, \dots,\, 196.

The common difference of this arithmetic series is 4. There would be (196 - 4) / 4 + 1 = 49 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 49 \times (4 + 196) = 4900 \end{aligned}

Positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 7 include:

7,\, 14,\, \dots,\, 196.

The common difference of this arithmetic series is 7. There would be (196 - 7) / 7 + 1 = 28 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 28 \times (7 + 196) = 2842 \end{aligned}

Positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 28 (integers that are both multiples of 4 and multiples of 7) include:

28,\, 56,\, \dots,\, 196.

The common difference of this arithmetic series is 28. There would be (196 - 28) / 28 + 1 = 7 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 7 \times (28 + 196) = 784 \end{aligned}.

The requested sum will be equal to:

  • the sum of all integers from 1 to 199,
  • minus the sum of all integer multiples of 4 between 1\! and 199\!, and the sum integer multiples of 7 between 1 and 199,
  • plus the sum of all integer multiples of 28 between 1 and 199- these numbers were subtracted twice in the previous step and should be added back to the sum once.

That is:

19900 - 4900 - 2842 + 784 = 12942.

8 0
3 years ago
Cylinder has a height of 15 centimeters and a radius of 10 centimeters. What is its volume? Use ​ ≈ 3.14 and round your answer t
tatuchka [14]

Answer: 4712.39 centimeters

Step-by-step explanation: Using the volume of a cylinder calculator, I got the answer of 4712.3889803847 centimeters, but rounded it to the nearest hundreth. Hope this helps!

3 0
3 years ago
Find the slope please help!
Sidana [21]

Answer:

4.5 is the answer 9/2=4.5

Step-by-step explanation:

4 0
3 years ago
Tema: Operadores Matemáticos<br><br><br>a*b=4a+5b
zhenek [66]
Yes it does bdffgjkhhh BGC. Bc. G. G. G. Y. Y. Y
4 0
3 years ago
On the function machine shown below, the function rule is given as a variable expression. When the output is 99, what is the inp
beks73 [17]

Answer: option d.

Step-by-step explanation:

We have the function:

y = f(x) = x^2  - 1

The output is 99 when y = 99, and the input is x.

Then we need to solve:

y = 99 = x^2 - 1

for x.

99 = x^2 - 1

99 + 1  =x^2

100 = x^2

√100 = x

10 = x

The correct option is d, input equals 10.

7 0
3 years ago
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