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AysviL [449]
2 years ago
9

The table below shows the costs of purchasing certain numbers of tablets we can assume that the total cost is a linear function

of the number of tablets purchased Number of tablets X 17 | 22 | 25 total cost in dollars Y 10183.00| 13178.00 | 14975.00​
Mathematics
1 answer:
SpyIntel [72]2 years ago
8 0

Answer:

hmmmm sry dk

Step-by-step explanation:

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Find DF AC=600 CB=480 AB=360
Mandarinka [93]
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6 0
3 years ago
(a) Let R = {(a,b): a² + 3b <= 12, a, b € z+} be a relation defined on z+)
grin007 [14]

Answer:

R is an equivalence relation, since R is reflexive, symmetric, and transitive.

Step-by-step explanation:

The relation R is an equivalence if it is reflexive, symmetric and transitive.

The order to options required to show that R is an equivalence relation are;

((a, b), (a, b)) ∈ R since a·b = b·a

Therefore, R is reflexive

If ((a, b), (c, d)) ∈ R then a·d = b·c, which gives c·b = d·a, then ((c, d), (a, b)) ∈ R

Therefore, R is symmetric

If ((c, d), (e, f)) ∈ R, and ((a, b), (c, d)) ∈ R therefore, c·f = d·e, and a·d = b·c

Multiplying gives, a·f·c·d = b·e·c·d, which gives, a·f = b·e, then ((a, b), (e, f)) ∈R

Therefore R is transitive

From the above proofs, the relation R is reflexive, symmetric, and transitive, therefore, R is an equivalent relation.

Reasons:

Prove that the relation R is reflexive

Reflexive property is a property is the property that a number has a value that it posses (it is equal to itself)

The given relation is ((a, b), (c, d)) ∈ R if and only if a·d = b·c

By multiplication property of equality; a·b = b·a

Therefore;

((a, b), (a, b)) ∈ R

The relation, R, is reflexive.

Prove that the relation, R, is symmetric

Given that if ((a, b), (c, d)) ∈ R then we have, a·d = b·c

Therefore, c·b = d·a implies ((c, d), (a, b)) ∈ R

((a, b), (c, d)) and ((c, d), (a, b)) are symmetric.

Therefore, the relation, R, is symmetric.

Prove that R is transitive

Symbolically, transitive property is as follows; If x = y, and y = z, then x = z

From the given relation, ((a, b), (c, d)) ∈ R, then a·d = b·c

Therefore, ((c, d), (e, f)) ∈ R, then c·f = d·e

By multiplication, a·d × c·f = b·c × d·e

a·d·c·f = b·c·d·e

Therefore;

a·f·c·d = b·e·c·d

a·f = b·e

Which gives;

((a, b), (e, f)) ∈ R, therefore, the relation, R, is transitive.

Therefore;

R is an equivalence relation, since R is reflexive, symmetric, and transitive.

Based on a similar question posted online, it is required to rank the given options in the order to show that R is an equivalence relation.

Learn more about equivalent relations here:

brainly.com/question/1503196

4 0
2 years ago
TIMED***Which equation is represented by the graph below?
Anuta_ua [19.1K]
   
From the graph we observe:  
If x = 0 then y = 1/2    (because  e⁰ = 1)

\displaystyle \bf \\
\Longrightarrow~~\boxed{\bf y =  \frac{1}{2} e^x}



8 0
3 years ago
Which number satisfies the inequality 9h + 15 > 55?
telo118 [61]
9h + 15 > 55
     - 15    - 15
9h > 40
h > 40/9
h > 4.44444.
any number greater than 4.44444
4 0
3 years ago
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Which expression are equivalent to the one below 36^x /6^x
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Step-by-step explanation:


8 0
3 years ago
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