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butalik [34]
3 years ago
13

Tema: Operadores Matemáticosa*b=4a+5b

Mathematics
1 answer:
zhenek [66]3 years ago
4 0
Yes it does bdffgjkhhh BGC. Bc. G. G. G. Y. Y. Y
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A test is worth 100 points. The test is made up of 40 items. Each item is worth either 2 points or 3 points. Which matrix equati
lidiya [134]

Answer:

Total number of points in the test = 100

Total number of items in the test = 40

Let number of items of 2 points be x and number of items of 3 points be y.

Now, using the given information the situation can be represented by using the following equations :

⇒ x + y = 40 .........(1)

⇒ 2x + 3y = 100 .........(2)

The matrix equation is :

\begin{bmatrix}1 & 1\\ 2& 3\end{bmatrix}\cdot \begin{bmatrix}x\\ y\end{bmatrix}=\begin{bmatrix}40\\ 100\end{bmatrix}

By solving the equation (1) and equation (2), we get :

Solution : x = 20 and y = 20

4 0
3 years ago
Read 2 more answers
I need help finding
Varvara68 [4.7K]

Answer:

the correct answer will be b/c

4 0
2 years ago
Read 2 more answers
What is the slope of the line that passes through the points A(0, 1) and B(2, 7)?
Alenkinab [10]

Answer:

3

Step-by-step explanation:

We can use the formula [ y2-y1/x2-x1 ] to solve.

7-1/2-0

6/2

3

Best of Luck!

4 0
3 years ago
What is the mean absolute deviation of the following set of data 4 6 2 8
babymother [125]

Answer:

srry i really need points

Step-by-step explanation:

6 0
2 years ago
Joe has eaten 2/5 of a pizza. James has eaten 1/7. How many times more pizza has Joe eaten than James?
11Alexandr11 [23.1K]
First let's make the denominators of the fractions equal.
To do this, we have to find a number which both 5 and 7 divide into.
The smallest number that does this is 35.

2  --> Multiply the numerator by 7
--   
5  --> Multiply the denominator by 7 to get 35

= 14/35

1 --> Multiply the numerator by 5
--
7 --> Multiply the denominator by 5 to get 35

= 5/35

Joe has eaten 14/35 and James has eaten 5/35.
14 / 5 = 2.8

<u>Joe has eaten 2.8 (or 2 4/5) times more pizza than James.</u>




8 0
3 years ago
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