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butalik [34]
3 years ago
13

Tema: Operadores Matemáticosa*b=4a+5b

Mathematics
1 answer:
zhenek [66]3 years ago
4 0
Yes it does bdffgjkhhh BGC. Bc. G. G. G. Y. Y. Y
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Fiona and her friends are playing a game by guessing where a coin will land when it is randomly dropped inside the square shown
Butoxors [25]

i'm 85% certain the answer is C. Fiona is not correct because the coin will definitely land in the white area .

8 0
3 years ago
Write the following ratio as a fraction in lowest terms <br> 5/3to7/6
zmey [24]

10/7

hope it helps...!!!

3 0
2 years ago
how many ways are there to win the jackpot? how many ways are there to match 5 of 6 numbers? how many ways are there to match 4
musickatia [10]

The number of ways to  match 5 of 6 numbers is 6 ways

The number of ways to  match 4 of 6 numbers is 15 ways

The number of ways to  match 3 of 6 numbers is 20 ways

To calculate number of ways to match 5 of 6 numbers we have to use to formula:

nCr =\frac{n!}{(n - r)! . r !}

6C5=\frac{6!}{(6-5)! . 5!}

6C5=\frac{6!}{(1)! . 5!}

6C5=\frac{6.5.4.3.2.1}{1.5.4.3.2.1}

6C5=\frac{6}{1}

6C5= 6 \ ways

∴ 6 ways are to match 5 of 6 numbers

To calculate number of ways to match 4 of 6 numbers we have to use to formula:

nCr =\frac{n!}{(n - r)! . r !}

6C4=\frac{6!}{(6-4)! . 4!}

6C4=\frac{6!}{(2)! . 4!}

6C4=\frac{6.5.4.3.2.1}{2.1.4.3.2.1}

6C4=\frac{30}{2}

6C4= 15 \ ways

∴ 15 ways are to match 4 of 6 numbers

To calculate number of ways to match 4 of 6 numbers we have to use to formula:

nCr =\frac{n!}{(n - r)! . r !}

6C3=\frac{6!}{(6-3)! . 3!}

6C3=\frac{6!}{(3)! . 3!}

6C3=\frac{6.5.4.3.2.1}{3.2.1.3.2.1}

6C3=\frac{120}{6}

6C3= 20 \ ways

∴ 20 ways are to match 3 of 6 numbers

Learn more about Jackpots here :

brainly.com/question/27116420

#SPJ4

6 0
2 years ago
The second term in a geometric series is 10, and the seventh term is 10,240. Find the sum of the first six terms.
just olya [345]

Answer:

The sum of the first 6 terms is 3,412.5.

Step-by-step explanation:

The second term of the geometric series is given by:

a_{2}=a_{1}*r

Where a1 is the first term and r is the common ratio. The seventh term can be written as a function of the second term as follows:

a_{7}=a_{1}*r^{6} \\a_{7}=a_{2}*r^{5} \\10,240 = 10*r^{5}\\r=\sqrt[5]{1024} \\r = 4

The sum of "n" terms of a geometric series is given by:

a_{1} = \frac{10}{4} = 2.5\\S_{n}=a_{1}(\frac{r^{n}-1 }{r-1})\\S_{6}=2.5(\frac{4^{6}-1 }{4-1})\\S_{6}=3,412.5

The sum of the first 6 terms is 3,412.5.

5 0
3 years ago
Summit provides patrol 6 (grade 6) with $85 to spend on the snacks. Will the amount of money be enough to cover the total cost o
sammy [17]

Answer: yes

Step-by-step explanation: smart werewolf.

3 0
3 years ago
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