Suppose that the speed at which cars go on the freeway is normally distributed with mean 65 mph and
1 answer:
Answer:
B) the probability that is traveling more than 63 mph is 0.6293 (or 62.93%)
Step-by-step explanation:
<u>Given:</u>
- Normally Distributed
- Mean (μ) = 65 mph
- Standard Deviation (σ) = 6 miles per hour
<u>Finding the Probability:</u>
If one car is randomly chosen, we want the probability that is traveling more than 63 mph is,
P(X > 63)
To find the value of z,
z = x - μ / σ
- z is the standard score
- x is the observed value
- μ is the mean of the sample
- σ is the standard deviation of the sample
z = 63 - 65 / 6
z = -2 / 6
z = -1 / 3 which is approximately -0.33
<u>Using Z table (attached below):</u>
- z = -0.33
to find this on the table
- on the vertical side under z go to -0.3
- on the horizontal next to z, go to .03
The area under the curve is 0.3707
P(z > 63) = 1 - P(z < 63)
= 1 - 0.3707
= 0.6293
Hence the probability that is traveling more than 63 mph is 0.6293
Learn more Probability from a similar example: brainly.com/question/15565069
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