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2 years ago

How can you use 1300 divided by 13 to help you find 1,287 divided 13

Mathematics

1 answer:

tiny-mole [99]2 years ago

6 0

Answer:

Step-by-step explanation:

This question is about the benefits of estimation.

1300/13 is easy and results in 100.

1287/13 can be approximated by 1300/13: 1287/13 ≈ 100.

Actually, 1287 = 1300 - 13 = 13(99); just subtract 1 from 100.

So: 1287/13 = 1300 - 13 = 1287. A nice bit of mental math!

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Please help me with this

Evgesh-ka [11]

The probability of not picking a red marble is 0.2.

The probability of picking a yellow or green marble is 0.5

The probability of drawing an even number of a number greater than 4 is 1.

The probability of getting heads and an even number is 1.

The probability of drawing a 2 or a 4 is 0.25.

<h3>What are the probabilities?</h3>

Probability determines how likely it is for an event to happen. The chances of the event occurring lies between 1 and 0.

The probability of not picking a red marble = (number of all the marbles - red marbles) / total marbles

4/20 = 0.2

The probability of picking a yellow or green marble = (number of yellow marbles / total number of marbles) + (number of green marbles / total number of marbles)

2/20 + 8/20 = 10/20 = 0.5

The probability of drawing an even number of a number greater than 4 = (number of even numbers / total numbers) + (numbers greater than 4 / total numbers)

5/10 + 5/10 = 1

The probability of getting heads and an even number is = (side that is head / total sides) x (even numbers on a die / total numbers on a die)

1/2 x 3/6 = 1

The probability of drawing a 2 or a 4 = 1/8 + 1/8 = 2/8 = 0.25

To learn more about probability, please check: brainly.com/question/13234031

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7 0

1 year ago

Select the correct answer. which hyperbola has both foci lying in the same quadrant? a. b. c. d.

faltersainse [42]

The hyperbola having both foci lying in the same quadrant is (y - 16)²/9² - (x + 1)²/12² = 1, making the 4th option a right choice.

For the hyperbola with an equation of the form (x - h)²/a² - (y - k)²/b² = 1, the foci in on the points (h + c, k) and (h - c, k), where c = √(a² + b²).

For the hyperbola with an equation of the form (y - k)²/a² - (x - h)²/b² = 1, the foci in on the points (h, k + c) and (h, k - c), where c = √(a² + b²).

Among the options:

(a) (x - 24)²/24² - (y -1)²/7² = 1.

The equation is of the form (x - h)²/a² - (y - k)²/b².

h = 24, k = 1, a = 24, b = 7.

c = √(a² + b²) = √(24² + 7²) = √(576 + 49) = √625 = 25.

Thus, foci are at the points (h + c, k), (h - c, k) = (24 + 25, 1), (24 - 25, 1) = (49, 1), and (-1, 1), which are in different quadrants.

(b) (y - 12)²/5² - (x - 6)²/12² = 1.

The equation is of the form (y - k)²/a² - (x - h)²/b².

h = 6, k = 12, a = 5, b = 12.

c = √(a² + b²) = √(5² + 12²) = √(25 + 144) = √169 = 13.

Thus, foci are at the points (h, k + c), (h, k - c) = (6, 12 + 13), (6, 12 - 13) = (6, 25), and (6, -1), which are in different quadrants.

The equation is of the form (y - k)²/a² - (x - h)²/b².

h = 2, k = 16, a = 15, b = 8.

c = √(a² + b²) = √(15² + 8²) = √(225 + 64) = √289 = 17.

Thus, foci are at the points (h, k + c), (h, k - c) = (2, 16 + 17), (2, 16 - 17) = (2, 33), and (2, -1), which are in different quadrants.

(d) (y - 16)²/9² - (x + 1)²/12² = 1.

The equation is of the form (y - k)²/a² - (x - h)²/b².

h = -1, k = 16, a = 9, b = 12.

c = √(a² + b²) = √(9² + 12²) = √(81 + 144) = √225 = 15.

Thus, foci are at the points (h, k + c), (h, k - c) = (-1, 16 + 15), (-1, 16 - 15) = (-1, 31), and (-1, 1), which are in the same quadrants (QUADRANT II).

Thus, the hyperbola having both foci lying in the same quadrant is (y - 16)²/9² - (x + 1)²/12² = 1, making the 4th option a right choice.

Learn more about the foci of a hyperbola at

brainly.com/question/9384729

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For the options, refer the image.