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polet [3.4K]
3 years ago
12

An observation deck extends 120 feet out above a valley. The deck sits 70 feet above the valley floor. If an object is dropped f

rom the observation​ deck, its height h in​ feet, after t​ seconds, is given by h equals negative 16 t squared plus 70. How long will it take for the object to be 6 feet above the valley​ floor? It will take ____ seconds for the object to be 6 feet above the valley floor.
Mathematics
1 answer:
Rzqust [24]3 years ago
8 0

Answer:

2

Step-by-step explanation:

The height formula given is:

h = -16t^2 + 70

That means the object will be initially (t=0) at the height 70 feet, from where it will be dropped.

If we want to know the time when the object will be at height 6 feet, we just need to use h=6 in the equation, and then calculate the value of t:

6 = -16t^2 + 70

16t^2 = 64

t^2 =4

t = 2 s

So, it will take 2 seconds for the object to be 6 feet above the valley floor.

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10(2^×) + 7(3^×) = 6^× + 70​
Mkey [24]

Answer:

x = 2.81 and 2.096

Step-by-step explanation:

Given the expression

10(2^x) + 7(3^x) = 6^x + 70​

This can also be expressed as;

10(2^x) + 7(3^x) = (2*3)^x + 70

10(2^x) + 7(3^x) = 2^x*3^x + 70

Let a  = 2^x and b = 3^x

10a + 7b = ab + 70

10a + 7b - ab = 70

10a-ab + 7b - 70 = 0

a(10-b)+7(b-10) = 0

a(10-b)-7(10-b) = 0

a-7 = 0 and 10-b = 0

a = 7 and b = 10

Since a = 2^x

7 = 2^x

log 7 = log2^x

log7 = xlog2

x = log7/log2

x = 2.81

Similarly

10 = 3^x

log 10 = log 3^x

log 10 = xlog3

x = log 10/log 3

x = 1/0.4771

x = 2.096

Hence the values of x that satisfies the equation are 2.81 and 2.096

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