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Let A = area
Let w = width
Let (w + 5) = length
A = (w + 5)w
The answer is 5.13 in²
Step 1. Calculate the diameter of the circle (d).
Step 2. Calculate the radius of the circle (r).
Step 3. Calculate the area of the circle (A1).
Step 4. Calculate the area of the square (A2).
Step 5. Calculate the difference between two areas (A1 - A2) and divide it by 4 (because there are total 4 segments) to get <span>the area of one segment formed by a square with sides of 6" inscribed in a circle.
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Step 1:
The diameter (d) of the circle is actually the diagonal (D) of the square inscribed in the circle. The diagonal (D) of the square with side a is:
D = a√2 (ratio of 1:1:√2 means side a : side a : diagonal D = 1 : 1 : √2)
If a = 6 in, then D = 6√2 in.
d = D = 6√2 in
Step 2.
The radius (r) of the circle is half of its diameter (d):
r = d/2 = 6√2 / 2 = 3√2 in
Step 3.
The area of the circle (A1) is:
A = π * r²
A = 3.14 * (3√2)² = 3.14 * 3² * (√2)² = 3.14 * 9 * 2 = 56.52 in²
Step 4.
The area of the square (A2) is:
A2 = a²
A2 = 6² = 36 in²
Step 5:
(A1 - A2)/4 = (56.52 - 36)/4 = 20.52/4 = 5.13 in²
The Original length of each side of square was 14.25 inches.
Step-by-step explanation:
Perimeter of a square is given by:
Perimeter = 4 * side
Let x be the original length of each side of square
So
decreasing 2 inch will mean
Perimeter of square after reducing 2 inches from each side
So,
The Original length of each side of square was 14.25 inches.
Keywords: Perimeter, square
Learn more about perimeter at:
#LearnwithBrainly
7x-4 because no x^2 is present. #brainliest pls??
Answer
1) x = 8
2) x = 1/3y + -5/3z
3) x = -1/2y + -3/4z + -1/2
Hope this helps:))
