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Helga [31]
2 years ago
9

A molecule that can be used as a molecular clock has a neutral mutation rate of one mutation per 12 million years. How many year

s ago did two species share a common ancestor if the molecules found in these two species differ by a total of six mutations?
a 1.5 million years
b 72 million years
c 12 million years
d 36 million years
Biology
1 answer:
Karolina [17]2 years ago
3 0

The years in which two species share a common ancestor if the molecules found in these two species differ by a total of six mutations is 72 million years.

<h3>What is mutation?</h3>

Mutation is the changing of gene or characters of any species over time, there are many reasons for mutation, like natural selection.

Every 12 million years, the molecular clock will mutate.

If the molecular clock experiences six mutations, 12 million years multiplied by 6 have passed.

12 x 6 = 72

Thus, the years are 72 million years. Option is b.

Learn more about mutation

brainly.com/question/13923224

#SPJ1

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Whose argument is stronger regarding the SAC curves and the LAC​ curve? A. The draftsman since the lowest point on each SAC curv
jarptica [38.1K]

NB: This is a business question, not biology.

Answer:

SAC (Short-run Average Cost) and LAC (Long-run Average Cost)

The stronger argument regarding the SAC (Short-run Average Cost) curves and the LAC (Long-run Average Cost) curves is:

A. The draftsman since the lowest point on each SAC curve will have a horizontal tangent line which only occurs at the lowest point on the LAC.

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The costs of all factors of production become variable in the long run.  But in the short-run, some costs are variable, and some are fixed.  When the producer starts operating over the long run period, it can then operate without the constraints imposed by the presence of the fixed-cost factors. Therefore, in the long run, the average cost (LAC) is equal to the short-run average cost (SAC) because there is an unconstrained minimum average cost at all output levels.

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Setler79 [48]

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