Answer:
34 square feet
Step-by-step explanation:
First, you need to find the other side of the garden in order to find the area a=l*w
The formula to find the length is, p-w*2=x x÷2=l
because, perimeter is l+l+w+w and area is just l*w
4.25*2=8.50
24.50-8.50=16
16÷2=8
l=8
So now we need to multiply the length and width to get the area.
8*4.25=34 sq. ft.
I hope that helps!
Answer:
x = 4
Step-by-step explanation:
2 + 3(3x - 6) = 5(x - 3) + 15
Expand the parenthesis:
2 + 9x - 18 = 5x - 15 + 15
Simplify:
9x - 16 = 5x
Subtract 5x from both sides:
4x - 16 = 0
Add 16 to both sides:
4x = 16
Divide both sides by 4:
x = 4
Answer:
See answer below
Step-by-step explanation:
The statement ‘x is an element of Y \X’ means, by definition of set difference, that "x is and element of Y and x is not an element of X", WIth the propositions given, we can rewrite this as "p∧¬q". Let us prove the identities given using the definitions of intersection, union, difference and complement. We will prove them by showing that the sets in both sides of the equation have the same elements.
i) x∈AnB if and only (if and only if means that both implications hold) x∈A and x∈B if and only if x∈A and x∉B^c (because B^c is the set of all elements that do not belong to X) if and only if x∈A\B^c. Then, if x∈AnB then x∈A\B^c, and if x∈A\B^c then x∈AnB. Thus both sets are equal.
ii) (I will abbreviate "if and only if" as "iff")
x∈A∪(B\A) iff x∈A or x∈B\A iff x∈A or x∈B and x∉A iff x∈A or x∈B (this is because if x∈B and x∈A then x∈A, so no elements are lost when we forget about the condition x∉A) iff x∈A∪B.
iii) x∈A\(B U C) iff x∈A and x∉B∪C iff x∈A and x∉B and x∉C (if x∈B or x∈C then x∈B∪C thus we cannot have any of those two options). iff x∈A and x∉B and x∈A and x∉C iff x∈(A\B) and x∈(A\B) iff x∈ (A\B) n (A\C).
iv) x∈A\(B ∩ C) iff x∈A and x∉B∩C iff x∈A and x∉B or x∉C (if x∈B and x∈C then x∈B∩C thus one of these two must be false) iff x∈A and x∉B or x∈A and x∉C iff x∈(A\B) or x∈(A\B) iff x∈ (A\B) ∪ (A\C).
Responder:
2³
5⁴
10³
a^6
Explicação passo a passo:
Quando um certo valor é multiplicado repetidamente,
Por exemplo,
a * a * a * a = a⁴ (a multiplicado 4 vezes)
Por isso,
2 x 2 x 2 = 2³
5 x 5 x 5 x 5 = 5⁴
10 x 10 x 10 = 10³
a x a x a x a x a x a = a^6
