Write down the value of 12^0

Use the spinner to find each probability. If the spinner lands on a line it is spun again.

BlackZzzverrR [31]

Answer:

110 / 3.6 = 30.555

Chance for yellow is about 31%

Orange is 70/3.6= 19.4444444

Orange is about 19%

Red is 40/3.6=11.11

Red is about 11

We divide by 3.6 because 360 degrees /100 percent = 3.6

The decimals are repeating so it is infinite decimal places

Yellow is about 31% (30.555555 for exact)

Orange is 19%(19.4444444 for exact)

Red is 11%(11.11111 for exact)

Step-by-step explanation:

4 0

3 years ago

Paige lives 3 miles east of her school. Diego lives & miles west of the school

Lerok [7]

Step-by-step explanation:

the question please .I can't answer without it.

3 0

3 years ago

Two boats are equidistant from a lighthouse. The boats are 30 miles apart. The angle formed between the two boats, with the ligh

anastassius [24]

Using the Law of Sines (sina/A=sinb/B=sinc/C for any triangle)

(sin40)/30=(sin(180-40)/2)/d

d=(30sin70)/sin40

d≈43.857mi

d≈44 mi to the nearest whole mile...

3 0

3 years ago

Read 2 more answers

What sample size is needed to give a margin of error within in estimating a population mean with 95% confidence, assuming a prev

atroni [7]

Answer:

$n = (\frac{1.96\sqrt{\pi(1-\pi)}}{M})^2$

The sample size needed is n(if a decimal number, round up to the next integer), considering the estimate of the proportion $\pi$ (if no previous estimate use 0.5) and M is the desired margin of error.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

The margin of error is of:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a p-value of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

Needed sample size:

The needed sample size is n. We have that:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$M = 1.96\sqrt{\frac{\pi(1-\pi)}{n}}$

$\sqrt{n}M = 1.96\sqrt{\pi(1-\pi)}$

$\sqrt{n} = \frac{1.96\sqrt{\pi(1-\pi)}}{M}$

$(\sqrt{n})^2 = (\frac{1.96\sqrt{\pi(1-\pi)}}{M})^2$

$n = (\frac{1.96\sqrt{\pi(1-\pi)}}{M})^2$

The sample size needed is n(if a decimal number, round up to the next integer), considering the estimate of the proportion $\pi$ (if no previous estimate use 0.5) and M is the desired margin of error.

4 0

3 years ago

Need help with this question please

Artemon [7]

Answer:

5%

Step-by-step explanation:

Explanation in attachment. Beware of the distraction.

6 0

2 years ago