Answer:
The probability of selecting a family with exactly one male child is 1/4 or 0.25.
Step-by-step explanation:
Given in the question,
possible outcomes for the children's genders
{FFFF, FFFM, FFMF, FMFF, MFFF, MFFM, MFMF, MMFF, FFMM, FMFM, FMMF, FMMM, MFMM, MMFM, MMMF, MMMM}
= 16
To find,
the probability of selecting a family with exactly one male child
<h3>Probability = favourable outcomes / possible outcomes</h3>
favourable outcomes = {FFFM, FFMF, FMFF, MFFF}
= 4
Probability = 4 / 16
= 1 / 4
= 0.25
Y= 13.18x + 36 Blank 1: 13.18 & Blank 2: 36
Answer:
F. Six times a number less nine
This is the only one that doesn't make sense
Sorry if im wrong
Answer:
0.078
Step-by-step explanation:
Margin of error = z√(p(1-p)/n)
Given
p-hat = 0.43
n = 270
z at 99% confidence interval = 2.576
Substitute
MOE = 2.576√0.43(1-0.43)/270
MOE = 2.576√0.43*0.57/270
MOE = 2.576√0.2451/270
MOE = 2.576*0.030129
MOE = 0.078
Hence the margin og error is 0.078
Answer: x = -5 1/7
Step-by-step explanation:
-22 - x = 5 + 6x + 9
First, combine the like terms 5 and 9
5 + 9 = 14
-22 - x = 14 + 6x
Add x to each side
-22 = 14 + 7x
Subtract 14 from each side
-36 = 7x
Divide each side by 7
x = -5 1/7 (Yes, a fraction.)
