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Andreas93 [3]
2 years ago
7

PLEASE HELP ASAP I WILL GIVE BRAINLIEST!!!!!!!!

Mathematics
2 answers:
Hoochie [10]2 years ago
8 0

Answer:

9:12 10:24

Step-by-step explanation:

First find their least common divisor which is 36. which means every 36 minutes they will flashes together.

just add the 36 to the time where they flash at the same time which is 8:00am

8:36 9:12 9:48 10:24 11:00 11:36

8090 [49]2 years ago
8 0

Answer: 9:12 and 10:24

Step-by-step explanation:

if we start from 8 am and add 12 minutes for light A in intervals and do the same for Light B we can see where the times are the same

Light A: 8:00, 8:12, 8:24, 8:36, 8:48, 9:00, 9:12, 9:24, 9:36, 9:48, 10:00, 10:12, 10:24, 10:36, 10:48, 11:00, 11:12, 11:24

Light B: 8:00, 8:18, 8:36, 8:54, 9:12, 9:30, 9:48, 10:06, 10:24, 10:42, 11:00, 11:18

9:12 and 10:24 are the correct answers because this is when the two lights flash at the same time

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hello loves!! I've been stuck on this question for like 2 hours lol! i need some help, ill give 100 points :)
lana66690 [7]

Answer:

61.12 units²

Step-by-step explanation:

(½ × pi × r²) + (½ × b × h)

½ [(3.14 × 4²) + (8 ×9)]

½(122.24)

61.12 units²

6 0
4 years ago
Read 2 more answers
Use (<, >, =) to compare 2⁄3 and 3⁄4.
Yakvenalex [24]

2/3<3/4

2/3 translates to 0.6666666666666

3/4 translates to 0.75

0.666666 is before 0.75 on a number line

8 0
3 years ago
The article "Snow Cover and Temperature Relationships in North America and Eurasia"† used statistical techniques to relate the a
poizon [28]

Answer:

Step-by-step explanation:

From the given information,

The ten observation data on october  snow cover for Eurasia  during the years is 6.5, 12.0, 14.9, 10.0, 10.7, 7.9, 21.9, 12.5, 14.5, 9.2

What would you report as a representative, or typical, value of October snow cover for this period, and what prompted your choice?

For the given data, 21.9 is an outlier, so trimmed mean would be good choice for the researcher,

Remove the smallest and the largest values to compute the trimmed mean

\bar x = \frac{12.0+14.9+10.0+10.7+7.9+12.5+14.5+9.2}{8} \\\\=\frac{91.7}{8} \\\\=11.465

6 0
3 years ago
If C(x) is the cost of producing x units of a commodity, then the average cost per unit is c(x) = C(x)/x. Consider the cost func
olga2289 [7]

Answer:

a. C(1,000) = 420,491.11

b. c(1,000) = 420.49

c. dC/dx(1,000) = 429.72

d. x = 900

e. c(900) = 420

Step-by-step explanation:

We have a cost function for x units written as:

C(x) = 54,000 + 240x + 4x^{3/2}

a. The total cost for x=1000 units is:

C(1,000) = 54,000 + 240(1,000) + 4(1,000)^{3/2}\\\\C(1,000)=54,000+240,000+4\cdot  31,622.78\\\\C(1,000)=54,000+240,000+ 126,491.11 \\\\C(1,000)=  420,491.11

b. The average cost c(x) can be calculated dividing the total cost by the amount of units:

c(1,000)=\dfrac{C(1,000)}{1,000}=\dfrac{ 420,491.11 }{1,000}= 420.49

c. The marginal cost can be calculated as the first derivative of the cost function:

\dfrac{dC}{dx}=240(1)+4(3/2)x^{3/2-1}=240+6x^{1/2}\\\\\\\dfrac{dC}{dx}(1,000)=240+6(1,000)^{1/2}=240+6\cdot 31.62=429.72

d. This value for x, that minimizes the average cost, happens when the first derivative of the average cost is equal to 0.

c(x)=\dfrac{C(x)}{x}=\dfrac{54,000+240x+4x^{3/2}}{x}=54,000x^{-1}+240+4x^{1/2}\\\\\\ \dfrac{dc}{dx}=54,000(-1)x^{-2}+0+4(1/2)x^{-1/2}=0\\\\\\\dfrac{dc}{dx}=-54,000x^{-2}+2x^{-1/2}=0\\\\\\2x^{-1/2}=54,000x^{-2}\\\\\\x^{-1/2+2}=54,000/2=27,000\\\\\\x^{3/2}=27,000\\\\\\x=27,000^{2/3}=900

e. The minimum average cost is:

c(900)=54,000(900)^{-1}+240+4(900)^{1/2}\\\\c(900)=60+240+120\\\\c(900)=420

7 0
3 years ago
Adult tickets for the school musical are sold for $3.50 and student tickets are sold for $2.50 on a given night 425 tickets were
miskamm [114]

Answer:

3.5x + 2.50y = 1237.50

425 = x + y

Step-by-step explanation:

number of adult tickets: x

number of student tickets: y

3.5x + 2.50y = 1237.50

( value of adult ticket [3.50]* number of adult tickets [x]) + (value of student ticket [2.50] * number of student tickets [y]) = total value (1237.50)

425 = x + y

(number of adult tickets [x]) + (number of student tickets [y]) = total (425)

7 0
3 years ago
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