Step-by-step explanation:
Evaluate:
-[-1⅘ ÷ 0.3(1.2)] - 5/6
⇛-[- 20/5 ÷ 0.3(1.2)]-5/6
⇛- [-20/5 ÷ 0.36] - 5/6
⇛-[-20/5 ÷ <em>36/100</em>] - 5/6
Here I have changed in expression decimal point into fraction by putting 100 in Denominator.
⇛-[-20/5 × 100/36] - 5/6
⇛-[(-20 × 100)/(5×36)] - 5/6
⇛-[-2000/180]-5/6
Remember (-) × (-) = +.
⇛2000/180 - 5/6
Now, LCM of the denominator 6 and 180 is 180.
⇛(2000 - 150)/180
⇛1850/180
Now, reduce the fraction by extracting and cancaling out by 2.
⇛825/80
Again reduce the fraction by extracting and cancaling out by 5.
⇛165/16 Ans.
Hope this helps!!
If we are concern only with the velocity of the particle along the x-axis, then, this implies that the velocity along the y-axis is hypothetically = 0ms^-1
∴ v = (vx=0,vy)
vy = 0ms^-1
vy = (dr/dt)y = 0ms^-1
ry→ = (2ct^2 -dt^3)j
dr/dt = 4ct - 3dt^2
4ct - 3dt^2 = 0
4c = 3dt
t = 4c/3d
First find the greatest common factor which is 3.
now write the GCF first, and then in parentheses, divide each term by the GCF;
3(108/3 + (-3x^2/3)
3(36 - x^2)
3(6^2 - x^2)
use the difference of squares;
3(6 + x)(6 - x)
hope this helped!
The answer is simple look first you have xy9/6, now if u want to go and answer and get the correct answer then you have to listen to mean
and you got it correct and if you think i'm wrong then your a idiot...