The correct answer to my knowledge would be 45.
Assuming that the 10 soils are each represented by A, B, C, D, E, F, G, H, I, J.
A can combine with 9 others as: AB AC AD AE A F AG AH AI AJ
B can combine as: BC BD BE BF BG BH BI BJ
C as: CD CE CF CG CH CI CJ
D as: DE DF DG DH DI DJ
E as: EF EG EH EI EJ
F as: FG FH FI FJ
G as: GH GI GJ
H as: HI HJ
I as: IJ
Once you add all the combinations together, you get 45.
Hoping this helped you!
Formula: Molarity = <span>Amount
of substance (in moles)/Volume of solution (in litres)</span>
40.0⋅g<span>/40</span>⋅<span>g⋅</span><span><span>mol</span><span>−1</span></span> ÷ (1.50⋅L) = 0.667 <span>−1</span>
sodium hydroxide.
The Molarity of
40 grams of Sodium Hydroxide in 1.50L of solution is 0.667 mol*L-1
<span> </span>
Answer:
There are a couple different possible answers, since there are multiple different structures that are present in both types of cells. So you have to make the choice of what to put.
The structures that prokaryotic and eukaryotic cells have in common are: plasma membrane, ribosomes, and cytoplasm
Answer:
a. True
Explanation:
Ribosomes are ribonucleoprotein complexes composed of RNA and proteins, which have two main roles 1-decode the message of the messenger RNA (mRNA) molecule and the formation of peptide bonds in the protein. For this purpose, each triplet of nucleotide bases or 'codon' in the mRNA sequence is used to assemble specific amino acids in the nascent polypeptide chain. Although different, both prokaryotic ribosomes and eukaryotic ribosomes are composed of two subunits: one small subunit that decodes the mRNA into a specific amino acid chain, and one large subunit that forms the peptide bonds in the polypeptide chain. Each ribosomal subunit is in turn composed of ribosomal RNAs and proteins. These ribosomal RNAs act as scaffolds by combining with proteins that assemble into ribosomes (i.e., small and large ribosome subunits).
