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kogti [31]
3 years ago
9

Create and show how to solve a problem with 3 fractions and involves multiplication and division. The problem should include can

celing and reciprocals.
Mathematics
1 answer:
Sladkaya [172]3 years ago
6 0
<span>1). 16 x 3/4 Step One- 16/1 x 3/4 Step two- 4 goes into 16 four times so cancel the 4 and change the 16 to a 4... Step three- 4 x 3=12 2). (81/16) divided by (9/14) Step one- Since its division we use (FREEZE CLAP FLIP)= Freeze (81/16) Clap the division sign and change it to a multiply sign and Flip the riprocals (9/14) The equation is now 81/16 X 14/9 Next 81 is divisible by 9 and 16 and 14 are divisible by 2 So the new formula i s 9/8 X 7/1 Solution=63/8 3). 2/3 divided by 4/3 Flip the reciprocals for the 4/3 New equation is 2/3 X 3/4 2 and 4 are divisible by 2 and the 3's cancel each other out Solution: 1/2</span>
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Need help finding the parallel and perpendicular slope
Rudik [331]

Answer:

Step-by-step explanation:

(x₁, y₁) = (19 , -4)   & (x₂ ,y₂) = (17, -20)

Slope =\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

        = \frac{-20-[-4]}{17-19}\\\\= \frac{-20+4}{17-19}\\\\= \frac{-16}{-2}\\\\= 8

m = 8

Parallel lines have same slope.

Parallel slope = 8

Slope of perpendicular line = \frac{-1}{m}

Perpendicular slope = \frac{-1}{8}

8 0
3 years ago
A paint company mixes it's paint with water to create more paint per gallon. They currently have ten gallon jugs which contain 1
Karo-lina-s [1.5K]
<h3>Answer:  1.25 gallons</h3>

==================================

Explanation:

They currently have ten gallon jugs that contain 10% water, so this means 0.10*10 = 1 gallon of the jug is water and the other 10-1 = 9 gallons is paint. This is assuming the cans are just paint and water.

The ratio of paint to water is 90:10 which reduces to 9:1

Often it helps to reduce as much as possible, but it's actually more handy in this case to keep it at 90:10 so you can see the two parts add back up to 100%

--------------

Let x be the amount of water we add. This amount is in gallons.

We start off with 1 gallon of water and it bumps up to 1+x gallons of water.

The overall amount of 10 gallons also bumps up to 10+x gallons.

We want a ratio of 80:20 this time, so we want 20 parts water and 80 parts paint. In other words, we want 20/(20+80) = 20/100 = 20% water

Divide (1+x) over (10+x) to get (1+x)/(10+x). This represents the fraction of water. We want this fraction to be equal to 0.20, which is the 20% water amount. It is also equal to 20/100.

--------------

(1+x)/(10+x) = 20/100

100(1+x) = 20(10+x) ... cross multiply

100+100x = 200+20x ... distribute

100x-20x = 200-100

80x = 100

x = 100/80 ... divide both sides by 80

x = 1.25

You need to add 1.25 gallons of water

--------------

If you add 1.25 gallons of water, then,

amount of water = 1+x = 1+1.25 = 2.25

amount of paint&water = 10+x = 10+1.25 = 11.25

So you'll have 2.25 gallons of water out of 11.25 gallons of water&paint mix

2.25/11.25 = 0.2 = 20% water

This confirms our answer.

--------------

Extra info:

1.25 gallons = 1 gallon + 1/4 gallon

1.25 gallons = 1 gallon + 1 quart

This is because 1 gallon = 4 quarts, so 1 quart = 1/4 gallon.

5 0
3 years ago
((sinB)/1+cosB) + ((1+cosB)/sinB) = 2cscB prove that the equation is an identity
Contact [7]

Step-by-step explanation:

If you need any explanation, we can communicate normally

4 0
2 years ago
(4x³-5x+10) ÷ (x+1)​
zlopas [31]

Answer:

4x^2 − 4x −1 + 11 / x+1

Step-by-step explanation:

The answer is

4x^2 − 4x −1 + 11 / x+1

4 0
3 years ago
Read 2 more answers
True or False<br> <img src="https://tex.z-dn.net/?f=%20i%5E%7B2%7D%20%3D%20%5Csqrt%7B2%7D%20" id="TexFormula1" title=" i^{2} = \
ivanzaharov [21]
I hope this helps you

3 0
3 years ago
Read 2 more answers
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