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dlinn [17]
3 years ago
11

a sporting complex charges $6 to use its facility. the expression 0.25b+6 models the total cost to hit b baseballs in the bating

cage. What is the cost per baseball?
Mathematics
1 answer:
Bond [772]3 years ago
7 0

Answer:

tndjxisjebducu

ejdjdnebdix

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How do I simplify (2k ^2 +5k-6) (3k-1)
wolverine [178]
(2k² + 5k - 6)(3k - 1)
(6k³ - 2k² + 15k² - 5k - 18k + 6)
6k² + 13k² - 23k + 6

Use the FOIL method to simplify the problem.
(FOIL stands for first outer, inner, last)
8 0
3 years ago
PLEASE HELP ME ANSWER IF YOU HURRY ILL GIVE POINTSSSS
sergij07 [2.7K]

Answer:

3rd one and the 4th one

Step-by-step explanation:

Hopt it helps.....

7 0
2 years ago
A random sample of 100 automobile owners in thestate of Virginia shows that an automobile is driven onaverage 23,500 kilometers
Anastaziya [24]

Answer:

a) 22497.7 < μ< 24502.3

b)  With 99% confidence the possible error will not exceed 1002.3

Step-by-step explanation:

Given that:

Mean (μ) = 23500 kilometers per year

Standard deviation (σ) = 3900 kilometers

Confidence level (c) = 99% = 0.99

number of samples (n) = 100

a) α = 1 - c = 1 - 0.99 = 0.01

\frac{\alpha }{2} =\frac{0.01}{2}=0.005\\ z_{\frac{\alpha }{2}}=z_{0.005}=2.57

Using normal distribution table, z_{0.005 is the z value of 1 - 0.005 = 0.995 of the area to the right which is 2.57.

The margin of error (e) is given as:

e= z_{0.005}\frac{\sigma}{\sqrt{n} }  = 2.57*\frac{3900}{\sqrt{100} } =1002.3

The 99% confidence interval = (μ - e, μ + e) = (23500 - 1002.3, 23500 + 1002.3) =  (22497.7, 24502.3)

Confidence interval = 22497.7 < μ< 24502.3

b) With 99% confidence the possible error will not exceed 1002.3

5 0
3 years ago
Please help with this
Maksim231197 [3]

Answer:

Choice A

Step-by-step explanation:

  • SSS is not applicable as only 2 sides are congruent
  • HL is lot applicable as triangles are not right angled (∠A and ∠E >90)
  • ASA also not applicable as the angle should be included but is not
5 0
3 years ago
The teachers’ editions of a statistics textbook sell for $150 each, and students’ editions of the book sell for $50 each. Which
Novay_Z [31]

Answer:

(300 + 50x)/(2 + x)

Step-by-step explanation:

Let the cost of teachers' edition books be t

Let the cost of students' edition books be s

So t = 150; s = 50

Then the total cost of 2 teachers' editions and x students' editions is 2t + sx = 2 × 150 + 50x = 300 + 50x.

The total number of books is 2 + x.

So the average cost per book is (300 + 50x)/(2 + x)

7 0
3 years ago
Read 2 more answers
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