Follow the steps to find the
1 answer:
The area of the sector rounded to 4 decimal place is 78.6396 cm²
<h3 /><h3>How to find the area of a sector?</h3>area of sector = ∅/ 360 × πr²
Therefore,
- r = radius
- ∅ = 46 degrees.
Hence,
area of a sector = 46 / 360 × 3.14 × 14²
area of a sector = 46 / 360 × 3.14 × 196
area of a sector = 46 / 360 × 615.44
area of a sector = 28310.24 / 360
area of a sector = 78.6395555556
Hence,
area of a sector = 78.6396 cm²
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Answer:
- h = -16t^2 + 73t + 5
- h = -16t^2 + 5
- h = -4.9t^2 + 73t + 1.5
- h = -4.9t^2 + 1.5
Step-by-step explanation:
The general equation we use for ballistic motion is ...
where g is the acceleration due to gravity, v₀ is the initial upward velocity, and h₀ is the initial height.
The values of g commonly used are -32 ft/s², or -4.9 m/s². Units are consistent when the former is used with velocity in ft/s and height in feet. The latter is used when velocity is in m/s, and height is in meters.
_____
Dwayne throws a ball with an initial velocity of 73 feet/second. Dwayne holds the ball 5 feet off the ground before throwing it. (h = -16t^2 + 73t + 5)
A watermelon falls from a height of 5 feet to splatter on the ground below. (h = -16t^2 + 5)
Marcella shoots a foam dart at a target. She holds the dart gun 1.5 meters off the ground before firing. The dart leaves the gun traveling 73 meters/second. (h = -4.9t^2 + 73t + 1.5)
Greg drops a life raft off the side of a boat 1.5 meters above the water. (h = -4.9t^2 + 1.5)
_____
<em>Additional comment on these scenarios</em>
The dart and ball are described as being launched at 73 units per second. Generally, we expect launches of these kinds of objects to have a significant horizontal component. However, these equations are only for <em>vertical</em> motion, so we must assume the launches are <em>straight up</em> (or that the up-directed component of motion is 73 units/second).
Answer:
Explanation:
The figure is not a regular hexagon. It is an irregular hexagon.
Please, find attached the picture with the original question and the figure.
You can split the figure into two triangles and one rectangle.
The rectangle has dimensions: 7units × 4units, thus its area is 28 units².
Both the upper triangle and lower triangle have base 7 units and height 2 units.
Hence the area of each triangle is:
Hence, the area of the hexagon is:
