Answer:
9 in
Step-by-step explanation:
We need to find x in x^3 > 600
For x=8, 8^3 = 512 < 600 (Too Small)
For x=9, 9^3 = 729 > 600 (Just right)
For x=10, 10^3 = 1000 > 600 (Too big)
Therefore, the smallest length of the cube-shaped box is 9 in.
We already know that the area of the rectangle increased by a square of the factor 7. So the dilated area of it (which we will call "Ad"), is:
Ad= (47)(7^2)
Ad= 47x49
Ad= 2303 m^2
What is the area of the dilated rectangle? The area of the dilated rectangle is 2303 m^2.
25% because if you simplify the fraction, it would be 1/4 and that is equal to 0.25
In the given diagram, line BG bisects ∠ABC and ∠DEF, m∠ABC= 112°, and ∠ABC≅∠DEF. So the measure of angles are :
1. m∠DEF= 112° because ∠ABC≅∠DEF
2. m∠ABG= 56° because a straight line BG is bisecting ∠ABC in two equal parts. So, 
3. m∠CBG= 56° because ∠ABG and ∠CBG are equal.
4. m∠DEG= 56° because ∠ABG ≅ ∠DEG
