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asambeis [7]
2 years ago
13

HELPPP3 1/5 ÷ 2/7=???​

Mathematics
1 answer:
kvasek [131]2 years ago
3 0

Answer:

11 1/5

Step-by-step explanation:

3 1/5 ÷ 2/7 =

16/5 ÷ 2/7 =

KCF (Keep, Change, Flip)

Keep 16/5

Change ÷ to ×

Flip 2/7 to 7/2

16/5 × 7/2

16 x 7 = 112

5 x 2 = 10

112/10

11 2/10

11 1/5

Hope that helps :)

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Miguel spent a total of $60 at the grocery store. Of this amount , he spent $18 on fruit. What percentage of the total did he sp
Paraphin [41]

Answer:

30%

Step-by-step explanation:

A percent can be found by dividing the part by the whole, or

part/whole

In this case, the part is the amount he spent on fruit. The whole is the total amount he spent.

amount spent on fruit/ total amount spent

He spent $18 on fruit, and $60 in total.

$18/ $60

Divide 18 by 60

18/60

0.3

Convert 0.3 to a decimal by multiplying by 100 or moving the deicaml place two spots to the right.

0.3*100=30

0.3--> 3.0 --> 30

30%

He spent 30% on fruit.

4 0
3 years ago
Like b and c are parallel what is the measure of <2
Vadim26 [7]
C
Hope this helps 8)
5 0
2 years ago
Help!! <br> Solve for v. <br> 14v - 10 = 14v
SashulF [63]

Answer:

sln

14v-10=14v

14v-14v=10

the Value of v don't get because when 14v-14v is equal to zero

6 0
2 years ago
What is the weight (in grams) of a liquid that exactly fills a 465.0 milliliter container if the density of the liquid is 0.982
Fynjy0 [20]

Answer:456.63

Step-by-step explanation:

8 0
2 years ago
Question: Researchers in Pakistan wanted to better understand the effects of anthracycline (a chemotherapeutic drug) on the hear
Sedbober [7]

Using the normal distribution, it is found that:

1. His z-score was of Z = -1.88.

2. There is a 0.0301 = 3.01% probability that a randomly selected person has a smaller E/A ratio than the patient in question 1.

3. Z-score of z = 1.85, there is a 0.0322 = 3.22% probability that a randomly selected patient has a higher E/A ratio.

4. Due to the higher absolute value of the z-score, the first patient had a more extraordinary result.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem:

  • The mean is of \mu = 1.35.
  • The standard deviation is of \sigma = 0.33.

Item 1:

Considering his ratio, we have that X = 0.73, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.73 - 1.35}{0.33}

Z = -1.88

His z-score was of Z = -1.88.

Item 2:

The probability is the <u>p-value of Z = -1.88</u>, hence, there is a 0.0301 = 3.01% probability that a randomly selected person has a smaller E/A ratio than the patient in question 1.

Item 3:

Score of X = 1.96, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{1.96 - 1.35}{0.33}

Z = 1.85

The probability is 1 subtracted by the p-value of Z = 1.85, hence, 1 - 0.9678 = 0.0322 = 3.22% probability that a randomly selected patient has a higher E/A ratio.

Item 4:

Due to the higher absolute value of the z-score, the first patient had a more extraordinary result.

More can be learned about the normal distribution at brainly.com/question/24663213

7 0
2 years ago
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