Newton's laws allow to find the result for the movement of the basketballl:
-
On the vertical axis the ball is on the ground.
- On the horizontal axis the ball is accelerating in the direction of the pushing force.
Newton's laws establish the relationship between the forces on objects:
- The 1st law states that if the net force is zero the object is stationary or with constant speed.
- The 2nd law gives a relation of the force with the mass and the acceleration of the body.
- The 3rd. Law states that the force appears in pairs, one on each body with the same magnitude, but in the opposite direction.
Let's apply these principles to the ball's motion diagram.
The two vertical forces are in the opposite direction, one is due to the weight of the body and the other is the attraction of the earth to the support of the ball, they are of equal magnitude, not their action-reaction force and reluctant because it is applied to the same body
In conclusion we can say that the ball is on the ground.
The two horizontal forces are in the opposite direction, the thrust force is greater than the friction therefore using Newton's second law the ball must be accelerating in the direction of the thrust force.
In conclusion we can say that the ball is accelerating in the direction of the pushing force.
In conclusion using Newton's laws we can find the result for the motion of the basketball:
-
On the vertical axis the ball is on the ground.
- On the horizontal axis the ball is accelerating in the direction of the pushing force.
Learn more about Newton's laws here: brainly.com/question/3715235
Rotational kinetic energy = Iω²/2 = 10
I = rotational inertia(moment of inertia)
ω= angular speed = 10 s⁻¹
∴ 10 = I(10²)/2
∴ I = 20/10² = 0.2 kg-m²
Answer:
1.87 A
Explanation:
τ = mean time between collisions for electrons = 2.5 x 10⁻¹⁴ s
d = diameter of copper wire = 2 mm = 2 x 10⁻³ m
Area of cross-section of copper wire is given as
A = (0.25) πd²
A = (0.25) (3.14) (2 x 10⁻³)²
A = 3.14 x 10⁻⁶ m²
E = magnitude of electric field = 0.01 V/m
e = magnitude of charge on electron = 1.6 x 10⁻¹⁹ C
m = mass of electron = 9.1 x 10⁻³¹ kg
n = number density of free electrons in copper = 8.47 x 10²² cm⁻³ = 8.47 x 10²⁸ m⁻³
= magnitude of current
magnitude of current is given as
= 1.87 A
Answer:
A. 64.0 J
Explanation:
Given parameters:
Spring constant = 800N/m
Extension = 0.4m
Unknown:
Work done = ?
Solution:
The work done in a string is given as:
Work done = 
x 800 x 0.4² = 64J
This can be solve by using the formula
F = p (1+ i)
Where F is the future population
P is the present population
I is the fraction increase
438 = 321*( 1 + I )
I = 0.36
<span>% increase 36%</span>
