Answer:
0.38 m
Explanation:
As we know that the person due to the airbag action, comes to a complete stop, in a time of 36 msec or less, and during this interval, is decelerated at a constant rate of 60 g, we can find the initial velocity (when airbag starts to work), as follows:
vf = v₀ -a*t
If vf = 0, we can solve for v₀:
v₀ = a*t = 60*9.8 m/s²*36*10⁻³s = 21.2 m/s
With these values of v₀, a and t, we can find Δx, applying any kinematic equation that relates these parameters with the displacement.
Just for simplicity, we can use the following equation:

where vf=0, v₀ =21.2 m/s and a= -588 m/s².
Solving for d:

⇒ d = 0.38 m
Explanation:
The given data is as follows.
Fluid is water so, density 
Weight flow rate = 500 lbf/s = 2224.11 N/sec
Cross-sectional area (A) = 
= 0.05184 
Hence, weight flow rate will be given as follows.
w = 
2224.11 N/sec = 
V =
m/s
= 4.373 m/s
Thus, we can conclude that average velocity in the given case is 4.373 m/s.
Answer:
0.6 Ω
Explanation:
As shown in the diagram below,
Since the resistance and the ammeter are connected in series,
(i) The same amount of current flows through them.
(ii) The sum of their individual individual voltage is equal to the total voltage of the circuit.
Applying ohm's law,
V = IR................ Equation 1
Where V = Voltage across the ammeter, I = current flowing through the ammeter, R = resistance of the ammeter.
make R the subject of the equation
R = V/I............... Equation 2
Given: V = 1.2-0.9 = 0.3 V, I = 0.5 A.
Substitute into equation 2
R = 0.3/0.5
R = 0.6 Ω
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