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3 years ago

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Physics

1 answer:

patriot [66]3 years ago

7 0

Answer:

220 V

Explanation:

$r_{1} = 20 ohm\\r_{2} = 30ohm\\r_{3} = 60ohm$

As the resistors are connected in series,

$R_{eq} = r_{1} +r_{2} +r_{3}$

= 20 + 30 + 60

= 110 ohms

V = IR

= 2 * 110

= 220 V

Hope it helps

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An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 1.50 mm. A 25

torisob [31]

Answer:

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The surface charge density is $1.474\times10^{-7}\ C/m^2$

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Explanation:

Given that,

Area =7.70 cm²

Distance = 1.50 mm

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Using formula of charge density

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Put the value into the formula

$\sigma=16666.66\times8.85\times10^{-12}$

$\sigma=1.474\times10^{-7}\ C/m^2$

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Using formula of capacitance

$C=\dfrac{\epsilon_{0}A}{d}$

Put the value into the formula

$C=\dfrac{8.85\times10^{-12}\times7.60\times10^{-4}}{1.50\times10^{-3}}$

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$q=CV$

Put the value into the formula

$q=4.484\times10^{-12}\times25.0$

$q=112.1\times10^{-12}\ C$

Hence, The electric field is 16666.66 V/m.

The surface charge density is $1.474\times10^{-7}\ C/m^2$

The capacitance is $4.484\times10^{-12}\ F$

The charge on each plate is $112.1\times10^{-12}\ C$

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