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Anastasy [175]
2 years ago
6

HELP Given: ABCD is a parallelogram and AC bisects BD. Prove: AC bisects

Mathematics
1 answer:
34kurt2 years ago
8 0

2) ABCD is a rhombus (a parallelogram with perpendicular diagonals is a rhombus)

3) \overline{AC} bisects \angle BCD (diagonals of a rhombus bisect the angles from which they are drawn)

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Write an equation passing through (-6,5) that is parallel to y=1/2x-7
charle [14.2K]

Answer:

y = 1/2x + 8

Step-by-step explanation:

a parallel equation needs to have the same slope as the given equation (1/2)

what we have so far is

y = 1/2x + b

since we know this has to pass through (-6, 5)

we’ll plug in -6 for x and 5 for y to find b

5 = 1/2(-6) + b

5 = -6/2 + b

5 = -3 + b

8 = b

so web. we plug b back into the equation

the final solution is

y = 1/2x + 8

4 0
3 years ago
What is the slope of the line that passes through the points (-9, -9) and (-9, -7) Write in simplest form.
dimaraw [331]

Answer:

Undefined slope, vertical line

Step-by-step explanation:

Slope = \frac{y_{2} -y_{1}}{x_{2}-x_{1}}

Slope = \frac{-7 -(-9)}{-9-(-9)} = \frac{-7+9}{-9+9} =\frac{2}{0} = Undefined

Since the slope is undefined, you would have a vertical line.

6 0
2 years ago
Suppose a simple random sample of size n is drawn from a large population with mean and standard deviation. The sampling distrib
ANTONII [103]

The sampling distribution of x has a mean μₓ = <u> μ </u> and standard deviation σₓ =​ <u> σ/√n </u>.

In the question, we are given that a random sample of size n is drawn from a large population with mean μ and standard deviation σ.

We are asked to find the mean and the standard deviation for the sampling distribution of the variable x for this sample.

The sample mean is regularly distributed, with a mean μₓ = μ and standard deviation σₓ = σ/√n, where n is the sample size, for samples of any size taken from populations that have a normal distribution.

Thus, the sampling distribution of x has a mean μₓ= <u> μ </u> and standard deviation σₓ=​ <u> σ/√n </u>.

Learn more about sampling distribution at

brainly.com/question/14467769

#SPJ4

The provided question is incomplete. The complete question is:

"Fill in the blanks to correctly complete the sentence below.

Suppose a simple random sample of size n is drawn from a large population with mean μ and standard deviation σ.

The sampling distribution of x has mean μₓ =​______ and standard deviation σₓ =​______."

4 0
2 years ago
In your own words what would the steps be to solve by graphing.
expeople1 [14]

Answer:

Graph the first equation.

Graph the second equation on the same rectangular coordinate system.

Determine whether the lines intersect, are parallel, or are the same line.

Identify the solution to the system. If the lines intersect, identify the point of intersection. ...

Check the solution in both equations.

Step-by-step explanation:

7 0
3 years ago
The axis of symmetry for the graph of the function is f(x) = x2 + bx + 10 is x = 6. What is the value of b?
joja [24]

Answer:

b=-12

Step-by-step explanation:

we have

f(x)=x^{2}+bx+10

we know that

The equation of a vertical parabola into vertex form is equal to

y=a(x-h)^{2} +k

where

(h,k) is the vertex of the parabola

and the axis of symmetry is equal to x=h

In this problem we have the axis of symmetry x=6

so

the x-coordinate of the vertex is equal to 6  

therefore

For x=6+1=7 -----> one unit to the right of the vertex

Find the value of f(7)

f(7)=7^{2}+b(7)+10

f(7)=59+7b

For x=6-1=5 -----> one unit to the left of the vertex

Find the value of f(5)

f(5)=5^{2}+b(5)+10

f(5)=35+5b

Remember that

f(5)=f(7) ------> the x-coordinates are at the same distance from the axis of symmetry

so

59+7b=35+5b ------> solve for b

7b-5b=35-59

2b=-24

b=-12


3 0
3 years ago
Read 2 more answers
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