Question

Which of the following integrals represents the area of the region bounded in the first quadrant by x = pi/ 4 and the functions f(x) = sec^2(x) and g(x) = sin(x)?

Answer 1

Answer:

option B is true.

Step-by-step explanation:

We are given that two functions

f(x)=$sec^2x$ and g(x)=sin x and a line x =$\frac{\pi}{4}$

We have to find the area of the region bounded in the first quadrant by x=${\pi}{4}$ and two functions

We know that the area bounded by two functions

=Integration of region(Upper curve- lower curve)

Therefore, function of sec square x is upper curve and function of sin x is lower function

Therefore, limit of x changing from 0 to $\frac{\pi}{4}$

Hence, the area of the region bounded in the first quadrant and two functions is given by

$=\int_{0}^{\frac{\pi}{4}} (sec^2x-sinx) dx$

Therefore, option B is true.