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Ghella [55]
3 years ago
13

Use the Pythagorean theorem to classify the triangle

Mathematics
2 answers:
bazaltina [42]3 years ago
8 0

The triangle with sides 5, 12, 13 is a right triangle because

a^2+b^2 = c^2

5^2+12^2 = 13^2

25+144 = 169

169 = 169

I'm using the pythagorean theorem converse.

Digiron [165]3 years ago
7 0

Answer:

they are equal

Step-by-step explanation:

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How many solutions does x2 - 10x=-25 have?
Elina [12.6K]

Answer:

4.2 Solving x2-10x+25 = 0 by Completing The Square . This quadratic equation has one solution only. That's because adding zero is the same as subtracting zero.

Step-by-step explanation:

3 0
3 years ago
SHOW YOUR WORK, <br><br>PLEASE HELP!!!!!!!!!
Shkiper50 [21]
To find the inverse, we swap the variables y and x, then solve for the new y.

3a. y=\frac{3}{x-1}

Swapping the variables: x=\frac{3}{y-1}
Solving for y: x(y-1)=3 \\ y-1= \frac{3}{x} \\ y=1+\frac{3}{x}
The domain of this inverse is x ≠ 0.
3b. y=x^2-1

Swapping: x = y^2 - 1
Solving for y: y^2 = x + 1 \\ y = \sqrt{x+1}
The domain of this inverse is x ≥ -1.
3c. y=\sqrt[3]{\frac{x-7}{3}}
Swapping: x=\sqrt[3]{\frac{y-7}{3}}
Solving for y: x^3=\frac{y-7}{3} \\ y-7=3x^3 \\ y=3x^3+7
The domain of this inverse is all real numbers.
4a. y=\frac{3}{x-1}, y=1+\frac{3}{x}
y=\frac{3}{(1+\frac{3}{x})-1} \\ y=\frac{3}{(\frac{3}{x})} \\ y=x
y=1+\frac{3}{(\frac{3}{x-1})} \\ y = 1+(x-1) \\ y = x

4c. y=\sqrt[3]{\frac{x-7}{3}}, y=3x^3+7
y=\sqrt[3]{\frac{(3x^3+7)-7}{3}} \\ y=\sqrt[3]{\frac{3x^3}{3}} \\ y=\sqrt[3]{x^3} \\ y=x
y=3(\sqrt[3]{\frac{x-7}{3}})^3+7 \\ y = 3({\frac{x-7}{3}})+7 \\ y = (x-7)+7 \\ y=x



3 0
3 years ago
jose jumped 8 1/3 feet. this was 2 1/3 feet farther than lila jumped. how far did lila jump TELL MEH AFTER THIS I GET ON IXL
nika2105 [10]
In this scenario Jose jumped the distance Lila jumped plus 2 1/3 ft, so...

Lilia + 2 1/3 = 8 1/3

subtract 2 1/3 from each side to get Lila by herself

Lila = 8 1/3 - 2 1/3
Lila = 6

Lila jumped 6 feet
5 0
3 years ago
If V = 12R / (r + R) , then R =
irina1246 [14]
V=\frac{12R}{r+R}\\\\V(r+R)=12R\\\\Vr+VR=12R\\\\VR-12R=-Vr\\\\(V-12)R=-Vr\ \ \ \ /:(V-12)\neq0\\\\R=\frac{-Vr}{V-12}\\\\R=\frac{Vr}{12-V}
7 0
3 years ago
Read 2 more answers
PLZ, I need help with problems 1 and 2! Thanks!
Harlamova29_29 [7]
1)
Parameter = 10+7+3+8+4+8+3+7
Parameter = 50 ft

2)
Area = Area 1 + Area 2

Area = (10x7) + (4x8)

Area = 70 + 32

Area = 102 Sq. Feet
8 0
3 years ago
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