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leva [86]
3 years ago
7

Andrew make six dollars an hour +9 dollars an hour for every hour of overtime overtime hours are any hours more than 40 hours fo

r the week. Create an equation that shows the amount of wages earned S for working why hours of overtime. Can’t remember to include in the equation the amount earned from working 40 hours
Mathematics
1 answer:
Anastaziya [24]3 years ago
8 0
If this person works a normal week plus overtime hours, then an equation for his total earnings would be

S(y) = ($6/hr)(40 hrs) + ($9/hr)y, where y is the # of overtime hours worked.
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Please I’ve attached the question can you help me
Andreyy89

Answer:

1. <em>n</em>[(A U B) - C] = {23, 24, 27, 29, 33, 36, 37, 39, 41, 42, 43, 45, 47, 48, 51, 53, 54, 57, 59, 61, 63}

2. <em>n</em>[(A - B) U C] = <em>n</em>[A U C] = {6, 10, 12, 15, 20, 23, 29, 30, 31, 37, 41, 43, 47, 53, 59, 60, 61}

3. D. I, II and III.

Step-by-step explanation:

U = {21, 22, 23, ..., 64}

A prime number is a number that can be divided only by 1 and itself.

A = {23, 29, 31, 37, 41, 43, 47, 53, 59, 61}

B = {24, 27, 30, 33, 36, 39, 42, 45, 48, 51, 54, 57, 60, 63}

C = {6, 10, 12, 15, 20, 30, 60}

1. Find <em>n</em>[(A U B) - C]

<em>n</em>(A U B) = {23, 24, 27, 29, 30, 33, 36, 37, 39, 41, 42, 43, 45, 47, 48, 51, 53, 54, 57, 59, 60, 61, 63}

<em>n</em>[(A U B) - C] = {23, 24, 27, 29, 30, 33, 36, 37, 39, 41, 42, 43, 45, 47, 48, 51, 53, 54, 57, 59, 60, 61, 63} - {6, 10, 12, 15, 20, 30, 60}

Since only 30 and 60 are common to <em>n</em>(A U B) and C, we therefore remove them it and have:

<em>n</em>[(A U B) - C] = {23, 24, 27, 29, 33, 36, 37, 39, 41, 42, 43, 45, 47, 48, 51, 53, 54, 57, 59, 61, 63}

2. Find <em>n</em>[(A - B) U C]

To get <em>n</em>(A - B) we remove all the elements of B in A. Since there are no common elements between A and B, we therefore have:

A - B = A = {23, 29, 31, 37, 41, 43, 47, 53, 59, 61}

C = {6, 10, 12, 15, 20, 30, 60}

Therefore, we have:

<em>n</em>[(A - B) U C] = <em>n</em>[A U C] = {6, 10, 12, 15, 20, 23, 29, 30, 31, 37, 41, 43, 47, 53, 59, 60, 61}

3. Which of the following is/are true?

I. A ∩ B = A ∩ C

A ∩ B = ∅

A ∩ C = ∅

Therefore, A ∩ B = A ∩ C is true.

II. A - B = A - C

A - B = A = {23, 29, 31, 37, 41, 43, 47, 53, 59, 61}

A - C = A = {23, 29, 31, 37, 41, 43, 47, 53, 59, 61}

Therefore, A - B = A - C is true.

III. A ∩ (B ∪ C) = ∅

A = {23, 29, 31, 37, 41, 43, 47, 53, 59, 61}

B U C = {6, 10, 12, 15, 20, 24, 27, 30, 33, 36, 39, 42, 45, 48, 51, 54, 57, 60, 63}

Therefore, A ∩ (B ∪ C) = ∅ is true.

Therefore, the correct option is D i.e. I, II and III are true.

4 0
3 years ago
Solve the equation by completing the square. round to the nearest hundredth if necessary. x^2-6x=20
amm1812
X^2 - 6x = 20
x^2 - 6x + 9 = 20 + 9
(x - 3)^2 = 29
x - 3 = (+-) sqrt 29
x = 3 (+-) sqrt 29
x = 3 (+-) 5.39

x = 3 + 5.39 = 8.39 <=
x = 3 - 5.39 = - 2.39 <=
6 0
3 years ago
Read 2 more answers
Plese help if you can. SCREENSHOT IS ATTACHED
xeze [42]

Step-by-step explanation:

So

WHOLE thing's rule (x,y)

(-1,6) one left 6 up

(1, -6) one right 6 down

(6,-1) six right one down

7 0
3 years ago
Read 2 more answers
Sort each equation according to whether it has one solution, infinitely many solutions, or no solution.
Sedaia [141]

Answer:

Equations with one solution: -2(x-3) = 2x-6

Equations with no solution:

6(x+5) = 6x+11\\5(x-2) = 5x-7

Equations with infinite many solutions: -3(x-4) = -3x+12

Step-by-step explanation:

We will solve each equation to see if it has one solution, no solution or infinite many solutions.

An equation where the value of variable can be found has one solution.

An equation with no solution has both sides different.

An equation with infinite solution will have both sides equal after solution(number)

So,

<u>Equation 1:</u>

5(x-2) = 5x-7

5(x-2) = 5x-7\\5x-10 = 5x-7\\5x-5x = -7+10\\0 = 3

As both sides are not equal, equation has no solution.

<u>Equation 2:</u>

-3(x-4) = -3x+12\\-3x+12 = -3x+12\\-3x+3x = -12+12\\0=0\\

As both sides are equal the equation has infinite many solutions.

<u>Equation 3:</u>

-2(x-3) = 2x-6\\-2x+6 = 2x-6\\-2x-2x = -6-6\\-4x = -12\\\frac{-4x}{-4} = \frac{-12}{-4}\\x = 3

As x=3, the equation has only one solution.

<u>Equation 4:</u>

6(x+5) = 6x+11\\6x+30 = 6x+11\\6x-6x+30 = 11\\30 =11

The equation has no solution.

Hence,

Equations with one solution: -2(x-3) = 2x-6

Equations with no solution:

6(x+5) = 6x+11\\5(x-2) = 5x-7

Equations with infinite many solutions: -3(x-4) = -3x+12

6 0
3 years ago
M is the midpoint of AB. AM = 9x-6, and BM = 6x+27 find x. find Am. Find BM.
MAXImum [283]

Answer:

x=11

Step-by-step explanation:

M is the midpoint this means that we can set AM and BM equal to eachother, once this is done we can solve for x

9x-6=6x+27 (set equal to eachother)

9x=6x+33 (add 6)

3x=33 (subtract 6x)

x=11 (divide by 3)


4 0
3 years ago
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