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Georgia [21]
3 years ago
15

To estimate the size of the grizzly bear population in a national park, rangers tagged and released 12 grizzly bears into the pa

rk. A few months later, 2 out of 21 grizzly bears sighted were tagged. Assuming the population of tagged bears in the population, estimate the number of grizzly bears in the population of this national park.
Mathematics
2 answers:
Allushta [10]3 years ago
3 0
All these ratios people are having trouble with today.

Its pretty easy once you get the hang of it.

So they release 12 grizzly.

We can say 12/x since we dont know the amount of grizzly bears in total.

We can then set 12/x equal to 2/21 and solve for x by using cross multiplication
Slav-nsk [51]3 years ago
3 0

Answer:

Its about 130

Step-by-step explanation:


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Effectus [21]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the data:

118, 124, 108, 116, 99, 125, 138, 118, 119, 121, 65, 130, 120

Ordered data:

65, 99, 108, 116, 118, 118, 119, 120, 121, 124, 125, 130, 138

1.)

90th percentile :

0.9(n + 1)th term

n = sample size = 13

0.9(14) th term

= 12.6th term

= (12 + 13)th / 2

= (130 + 138) / 2

= 134

Third quartile (Q3) = 75th percentile

0.75(n + 1)th term

n = sample size = 13

0.75(14) th term

= 10.5th term

= (10 + 11)th / 2

= (124 + 125) / 2

= 124.5

What is the first quartile?

First quartile (Q1) :

0.25(n + 1)th term

n = sample size = 13

0.25(14) th term

= 3.5th term

= (3 + 4)th / 2

= (108 + 116) / 2

= 112

(4) What is the 10th percentile?

0.1(n + 1)th term

n = sample size = 13

0.1(14) th term

= 1.4th term

= (1 + 2)th / 2

= (65 + 99) / 2

= 82

(5) 65tb percentile :

0.65(n + 1)th term

n = sample size = 13

0.65(14) th term

= 9.1th term

= (9 + 10)th / 2

= (121 + 124) / 2)

= 122.5

(6) What is the IQR?

Q3 - Q1

124.5 - 112

= 12.5

(7) What are the lower and upper limits?

Maximum = 138

Minimum = 65

4 0
3 years ago
The Wind Mountain excavation site in New Mexico is an important archaeological location of the ancient Native American Anasazi c
timurjin [86]

Answer:

a) 28

b)

Class Limits  Class Boundaries   Midpoint    f      Rf         Cf

10 - 37            9.5-37.5                   23.5            7     0.096     7      

38 - 65           37.5-65.5                 51.5           25    0.342     32    

66 - 93           65.5-93.5                 79.5          26    0.356     58    

94 -  121        93.5-121.5                   107.5         9     0.123       67    

122 - 149      121.5-149.5                  135.5         5      0.068     72  

150 - 177       149.5-177.5                  163.5        0         0.0      72    

178 - 205       177.5-20.5                  191.5         1       0.014      73  

Total                                                                  73          1.0    

c)

The histogram is in attached file.

Step-by-step explanation:

a)

The width of class interval=range/desired number of classes

The width of class interval=(maximum-minimum)/7

The width of class interval=(200-10)/7

The width of class interval=190/7

The width of class interval=27.14=28 (rounded to next whole number)

Part(b) and part (c) is explained in attached word document.

Download docx
5 0
3 years ago
How would you classify the decimal form of 7/25?
olga55 [171]
The answer is C to the question
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